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3 years ago

Write an equation in standard form for the circle shown.

Mathematics

1 answer:

Vika [28.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

The intercepted angle is given as "34x+4"

The arc is 196.

Any intercepted angle of an arc that falls in the opposite circumference, it will have a measure half that of the arc intercepted.

Hence,

34x+4 = (0.5)(196)

34x + 4 = 98

34x = 98 - 4

34x = 94

x = 94/34 = 2.76

Answer choice B is right.

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Line E: 5x + 5y = 40

Marianna [84]

Answer:

The correct answer is d, there are infinitely many solutions.

Step-by-step explanation:

If the variable terms are the same and the constants are the same, the equation has infinitely many solutions.

Ex: 5(3)+5(5)=40 3+5=8

5(4)+5(4)=40 4+4=8

Hope this helps! Brainliest please!

8 0

3 years ago

What is the area of the polygon ?

Effectus [21]

Answer:

C) 99 in²

Step-by-step explanation:

you can divide this shape by drawing a horizontal line to create a 4x12" rectangle and a trapezoid with a height of (10-4) in and bases of 12 and 5"

area of rectangle: 12 x 4 = 48

area of trapezoid: 1/2(6)(12+5) = 3(17) = 51

total area = 48 + 51

total area = 99 in²

7 0

2 years ago

Read 2 more answers

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

$E[ X ] = (np) (p +(1 - p))^{n -1 }= np.$

5 0

3 years ago

Estimate 1 5/5 plus 2 2/12

ELEN [110]

Answer:

I estimate bruh.

Step-by-step explanation:

5 0

3 years ago

Which is an equation of the line that goes through the points ( 4, 1) and

Aloiza [94]

Answer:

none of the above

Step-by-step explanation:

You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.

___

You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...

y = (y2 -y1)/(x2 -x1)·(x -x1) +y1

Filling in the given points, we get ...

y = (3 -1)/(2 -4)·(x -4) +1

y = 2/(-2)(x -4) +1 . . . . . simplify a bit

y = -x +4 +1 . . . . . . . . . simplify more

y = -x +5 . . . . . . . . . . . slope-intercept form

5 0

2 years ago