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2 years ago

Given the side measurements. classify the triangle as acute, right, obtuse, or not a triangle. 11, 4, 16

Mathematics

1 answer:

serg [7]2 years ago

3 0

Answer: not a triangle

Step-by-step explanation:

If this were to be a triangle, the shorter sides would be 11 and 4 and the longest side would be 16.

First, we should determine if it is a triangle.

Sum of shorter sides = 15
This is less than the longest side, 16, so therefore, it is not a triangle.

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P and a are both prime numbers. Find the values of p and q so that 6*54*p/q is a perfect cube.

daser333 [38]

6x54= 324

6x50=300

6x4=24

300+24=324

The previous nearest cube root is 216 and the next cube root would be 343.

p/q could be any prime number which there are a lot of.

im going to say p is 1 and q is 3

next you would divide 1 by 3

1/3=0.666666667

324x0.666666667=216 exact

3 0

3 years ago

What are the fourth roots of 6+6√(3i) ?

Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4 = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 = 12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0

3 years ago

Twin brothers, Billy and Bobby, can mow their grandparent's lawn together in 97 minutes. Billy could mow the lawn by himself in

s2008m [1.1K]

Answer:

52 minutes i think im not sure i'm not in high school

Step-by-step explanation:

5 0

3 years ago

which expressions are equivalent to the first one? I don't understand how to determine that so please explain. Thanks!

coldgirl [10]

9514 1404 393

Answer:

(a) -(x+7)/y

(b) (x+7)/-y

Step-by-step explanation:

There are several ways you can show expressions are equivalent. Perhaps the easiest and best is to put them in the same form. For an expression such as this, I prefer the form of answer (a), where the minus sign is factored out and the numerator and denominator have positive coefficients.

The given expression with -1 factored out is ...

$\dfrac{-x-7}{y}=\dfrac{1(x+7)}{y}=\boxed{-\dfrac{x+7}{y}} \quad\text{matches A}$

Likewise, the expression of (b) with the minus sign factored out is ...

$\dfrac{x+7}{-y}=\boxed{-\dfrac{x+7}{y}}$

On the other hand, simplifying expression (c) gives something different.

$\dfrac{-x-7}{-y}=\dfrac{-(x+7)}{-(y)}=\dfrac{x+7}{y} \qquad\text{opposite the given expression}$

Another way you can write the expression is term-by-term with the terms in alpha-numeric sequence (so they're more easily compared).

Given: (-x-7)/y = (-x/y) +(-7/y)

(a) -(x+7)/y = (-x/y) +(-7/y)

(b) (x+7)/(-y) = (-x/y) +(-7/y)

Of course, you need to know the use of the distributive property and the rules of signs.

a(b+c) = ab +ac

-a/b = a/(-b) = -(a/b)

-a/(-b) = a/b

Summary: The given expression matches (a) and (b).

_____

Additional comments

Sometimes, when I'm really stuck trying to see if two expressions are equal, I subtract one from the other. If the difference is zero, then I know they are the same. Looking at (b), we could compute ...

$\left(\dfrac{-x-7}{y}\right)-\left(\dfrac{x+7}{-y}\right)=\dfrac{-y(-x-7)-y(x+7)}{-y^2}\\\\=\dfrac{xy+7y-xy-7y}{-y^2}=\dfrac{0}{-y^2}=0$

Yet another way to check is to substitute numbers for the variables. It is a good idea to use (at least) one more set of numbers than there are variables, just to make sure you didn't accidentally find a solution where the expressions happen to be equal. We can use (x, y) = (1, 2), (2, 3), and (3, 5) for example.

The given expression evaluates to (-1-7)/2 = -4, (-2-7)/3 = -3, and (-3-7)/5 = -2.

(a) evaluates to -(1+7)/2 = -4, -(2+7)/3 = -3, -(3+7)/5 = -2, same as given

(b) evaluates to (1+7)/-2 = -4, (2+7)/-3 = -3, (3+7)/-5 = -2, same as given

3 0

3 years ago

789/548x-89/887=688/8724 find x

Olin [163]

$\frac{789}{548}x- \frac{89}{887}=\frac{688}{8724}$

first we try to semplify as much as possible the fractions.

First we decompose the numbers

789 = 3 * 263

548 = 2 * 2 * 137 = 2^2

they have nothing in common, so the first fraction remains so

89 = 89 (prime number)

887 = 887 (prime number)

they have nothing in common, so the second one remains so

688 = 2 * 2 * 2 * 2 * 43 = 2^4 * 43

8724 = 2 * 2 * 3 * 727 = 2^2 * 3 * 727

they have 2^2 (=4) in common, so the numerator and the denominator can be devided by 4

$\frac{688}{8724}= \frac{688:4}{8724:4}=\frac{172}{2181}$

so:

$\frac{789}{548}x- \frac{89}{887}=\frac{172}{2181}$

now we calculate the common denominator

take the scomposition:

548 = 2^2 * 137

887 = 887

2181 = 3 * 727

take every number one time

so the common denominator is 2^2 * 137 * 887 * 727 * 3 = 1'060'131'756

now calculate every single numerator: first we divide each denominator by the common denominator, then we moltiply the result with each numerator

first fraction: 789/548

1060131756 / 548 = 1934547

1934547 * 789 = 1526357583

second fraction: 89/887

1060131756 / 887 = 1195188

1195188 * 89 = 106371732

third one: 172/2181

1060131756 / 2181 = 486076

486076 * 172 = 83605072

now we can delete the common denominator

1526357583x - 106371732 = 83605072

solve it

1526357583x = 83605072 + 106371732

1526357583x = 189976804

x = 1526357583 / 189976804

decompose

1526357583 = 887 * 3 * 3 * 727 * 263

189976804 = 137 * 2 * 2 * 211 * 53 * 31

nothing in common

x = 1526357583 / 189976804

8 0

3 years ago