All categories

2 years ago

What is the surface area of the cube with the given edge length, s?

2 answers:

8 0

A cube has 6 sides.
first calculate the area of 1 side and then multiply it by 6

the area for one side = S^2 ( or SxS)

15^2 = 15 x 15 = 225 square inches

now multiply that by 6:
225 x 6 = 1350 square inches total

the answer is B.

ddd [48]2 years ago

3 0

Answer:

B. 1350 in^2

Step-by-step explanation:

You might be interested in

(1 point) Let f be a periodic function of period 10 such that f(x)=x2 for −5≤x<5. Then the Fourier series of f is

ehidna [41]

Answer:

The answer is " $\frac{25}{3}$ ".

Step-by-step explanation:

please find the complete question in the attached file.

$a_0=\frac{1}{10}\int^{5}_{x=-5} x^2 dx\\$

$=\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}$

7 0

2 years ago

How do I find perimeter and area

NARA [144]

Answer:

To find the perimeter of a rectangle or square you have to add the lengths of all the four sides

The area is measurement of the surface of a shape.

Hope this helps! （づ￣3￣）づ╭❤～

4 0

3 years ago

Plese help will give crown to best answer!!! 73 points!!! gx =4x +1 when g(3)

Lemur [1.5K]

G(3)=13 ,
13 will be answer

5 0

3 years ago

Read 2 more answers

Ok can someone help me thanks!!

kotegsom [21]

Answer:

A constant of $20 can be multiplied by the number of months to find the amount in the account.

Step-by-step explanation:

4×20=80

7×20=140

7 0

3 years ago

Read 2 more answers

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

2 years ago