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4 years ago

Fuaad solved an absolute value inequality and expressed the solution as -12

1 answer:

5 0

Inequalities require a sign of greater than, less than, greater than or equal to, or less than or equal to. It's never just a single number solution. It's always going to be a range of solutions

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Find the LCD to each the fractions and then add them together 1/4 + 2/5 + 1/3

jekas [21]

The LCD of these fractions is 60!

The sum of these fractions is $\frac{59}{60}$ !

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

6 0

3 years ago

Read 2 more answers

Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x > 0. In other words, express y(x) as a fun

MrMuchimi

Answer:

$y{x} = \sqrt{7+2Inx}$

Step-by-step explanation:

$y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}$

Let say; By y(x)= y(e)

we have;

$y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0$

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

$y^{1} (x) = 0 + 1/ xy$

$y^{1} = 1/xy$

dy/dx = 1/xy

$\int\limits {y} \, dxy = \int\limits \, dx/x$

$y^{2}/2 Inx + C$

RECALL: y(e) = 3

$(3)^{2} / 2 = In (e) + C$

$\frac{9}{2} =In(e)+C$

$\frac{9}{2} - 1 = C$

$\frac{7}{2} = C$

$y^{2} / 2 = In x +C$

$y^{2} / 2 = In x +7/2$

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

$y^{2} = {7+2Inx}$

$y{x} = \sqrt{7+2Inx}$

8 0

4 years ago

Alice needs 3/7 kilograms of flour for making a cake. How many of flour does she needs for making 42 cakes?

Oduvanchick [21]

Hey there!

3/7 is needed for 1 cake

If she needs to make 42 cakes, then multiply the amount for 1 by 42

42 × 3/7 = 126/7 = 18

She needs 18 kilograms of flour to make 42 cakes

Hope this helps :)

3 0

3 years ago

Ian has the choice of taking out a 25-year loan for $205,000 at 3.2% interest, compounded monthly, or the same loan at 20 years

PolarNik [594]

B. Less than $93,077

4 0

3 years ago

Read 2 more answers

Please help me ill give brainliest

Oksana_A [137]

Answer:

I think the answer is D!