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Yanka [14]
2 years ago
12

Which restriction is appropriate for the variable 4a + 12 / a + 3

Mathematics
2 answers:
bonufazy [111]2 years ago
5 0

I'll presume the slash is the fraction bar and the questioner is asking about

\dfrac{4a+12}{a+3}

That always equals 4 except when a=-3

So the restriction is

Answer:  a ≠ -3

Archy [21]2 years ago
4 0

Answer:

The restriction is at a=-3

Step-by-step explanation:

You need to see if there are like terms. If there are that is a hole. For example you can a 4 out of the equation like so.

4(a+3)/a+3.

since they both have a+3 that is a hole. so a+3=0 so a=-3 is a restriction

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Two answer left a or b? my mom said a but she not good with math plz help
Sergeu [11.5K]

A would be correct!!!

Glad I could help(:

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5 0
2 years ago
Read 2 more answers
The condition_______?proves that ∆ABC and ∆EFG are congruent by the SAS criterion.
snow_lady [41]

Answer:

(1)  D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.

Step-by-step explanation:

1)

From the given figure it is noticed that

AC=EG

CB=GF

According to SAS postulate,  if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.

The included angles of congruent sides are angle C and angle G.

So, condition "Angle C is congruent to to Angle F"  will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.

2)

If AB\neq EF

According to SSS postulate,  if all three sides in one triangle are congruent to the corresponding sides in the other.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.

3)

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.

\angle C\neq \angle G

Therefore angle C and angle F cannot be congruent to each other.

4 0
3 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
Assume that A varies directly with z. If A = 30 when z = 5, find A when z = 9.
pishuonlain [190]
If A varies directly with z, and A is 30 and z is 5, then when z is 1, A is 6.
z: 5 ÷ 5 = 1
A: 30 ÷ 5 = 6
Then, when z is 1, A is 6
So, when z is 9, A is...
z: 1 × 9 = 9
A: 6 × 9 = 54

A is 54
6 0
3 years ago
Read 2 more answers
In this diagram, which equation could you prove to be true in order to conclude that the lines are parallel?
Sladkaya [172]

THE ANSWER:

c−ab=de

THIS IS WHY:

4 0
3 years ago
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