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3 years ago

Before tax & after a 50%

Mathematics

1 answer:

Slav-nsk [51]3 years ago

8 0

Answer: The boots were marked $86.

Step-by-step explanation: We know Mica's total was $100 for the bill. He got the only hat left marked $12, and a pair of boots. Before tax and after a 50% sale, her total is $100. Since she spent $12 for the hat, we know the rest of the money is going towards the boots. The boots will cost $86.

Hat($12) + Boots($86) = 100

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At a hot air ballon festival, Erica spots a red ballon due east at an angle of elevation of 36 degrees. She turns due west and s

gulaghasi [49]

Answer:

Step-by-step explanation:

Given

Balloon in the east makes an angle of elevation of $36^{\circ}$ and is at height of 461 m

Balloon in the west makes an angle of elevation of $51^{\circ}$ and is at height of 296 m

Erica height is 1.6 m tall so net altitude of Red balloon is 459.4 m

and net height of Blue balloon is 294.4 m

using trigonometry

$\tan 36=\frac{459.4}{d_1}$

$\tan 51=\frac{294.4}{d_2}$

$d_1=632.30 m$

$d_2=238.4 m$

Distance between two Balloons

$d=d_1+d_2$

$d=870.70 m$

7 0

3 years ago

What is (a+b)(a-b) equal

Alja [10]

Answer:a squared-b squared

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Help will mark Brainliest!!

BartSMP [9]

Answer:

-20.5

Step-by-step explanation:

Using a basic calculator, you divide 10.25 by -.5 which easily gives -20.5

5 0

1 year ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

2 years ago

Read 2 more answers

You just reflected on working with right triangles and trigonometric concepts. How important were concepts that you learned prev

harina [27]

Idk if ya still need it or if this will help but this is what i put for mine

Concepts that I had previously learned about are quite important because math goes hand and hand. if you try to skip something and go ahead you'll most likely get confused because there could of been something highly important to that would help you understand whats ahead. in the previous unit it tells you about triangles and their description like a right triangle-90 degree angle and where legs and hypotenuse is located, this unit has had a ton about right triangles.

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3 years ago