To solve this problem you must apply the proccedure shown below:
1. You have the following logarithm:
<span>log(2)n=4
2. Therefore, you con rewrite it as below:
loga(b)=logb/loa
</span>
3. Therefore, you have:
log(2)n=4⇒log(n)/log(2)=4
4. Then, you obtain:
log(n)=4log(2)
5. Therefore, as you can see, the answer for the exercise shown above is the last option, which is:
log(n)=4log(2)
Answer:
277°
Step-by-step explanation:
The measure of arc AEG = AB + BE + EF + FG
The central angle is congruent to the arc that subtends it
∠ ECB = 180° - 44° = 136° ( adjacent angles )
∠ECF = ∠ ACB = 44° ( vertical angles ), thus
AEG = 44° + 136° + 44° + 53° = 277°
Answer:
<u>Option </u><u>D</u> (y = 5/6x -12).
Step-by-step explanation:
Hey there!
The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].
According to the question, the first line passes through point (12,6) and (0,-4).
So,



Therefore, the slope of the line is 5/6.
Now as per the condition of parallel lines, m1 =m2 = 5/6.
So, keeping the value of m2 in equation (i), we get;
(y+2) = 5/6(x-12)

or, y = 5/6x - 12.
Therefore, the required equation is y = 5/6 X - 12.
<u>Hope</u><u> </u><u>it </u><u>helps</u><u>!</u>