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arlik [135]
3 years ago
6

A wall is 15 ft. high and 10 ft. from a house.

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

Answer:

=11.35 ft.

Step-by-step explanation:

The ladder, the flat surface the wall and the height up to the window form a trapezium.

The triangle that constitutes of the trapezium has the ladder as the hypotenuse, the distance between the two walls as base and the perpendicular distance from the base of the ladder to the window as height.

The height=20.35 ft-15 ft= 5.35 ft

Distance between the walls=10 ft

Hypotenuse²= base²+height²

H²=b²+h²

=10²+5.35²

=128.6225

H=√128.6225

=11.35 ft.

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Use the distance formula to find the distance between the points given.
masha68 [24]

The distance between the points is 4\sqrt{13}

Step-by-step explanation:

The formula of the distance between two points (x_{1},y_{1}) and

(x_{2},y_{2}) is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

To find the distance between two point:

  • Put one of the two point as (x_{1},y_{1})
  • Put the other point as (x_{2},y_{2})
  • Substitute then in the rule of the distance and calculate the distance

∵ The two points are (18 , -2) and (6 , -10)

- Put (18 , -2) as (x_{1},y_{1}) and (6 , -10) as (x_{2},y_{2})

∴ x_{1} = 18 and x_{2} = 6

∴ y_{1} = -2 and y_{2} = -10

- Substitute them in the rule below

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∴ d=\sqrt{(6-18)^{2}+(-10--2)^{2}}

∴ d=\sqrt{(-12)^{2}+(-10+2)^{2}}

∴ d=\sqrt{(-12)^{2}+(-8)^{2}}

∵ (-12)² = 144 and (-8)² = 64

∴ d=\sqrt{144+64}

∴ d=\sqrt{208}

∵ \sqrt{208}=4\sqrt{13}

∴ d=4\sqrt{13}

The distance between the points is 4\sqrt{13}

Learn more:

You can learn more about the distance between two points in brainly.com/question/3969582

#LearnwithBrainly

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4 years ago
QA НА / Terrizzi read Best Buy's ad this past weekend. They are selling a 42 inch plasma TV for $349.99. If 42 inches is the dia
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Answer:

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3 years ago
Can you help me please i do. not get this
xenn [34]

Answer:

5 13/24

Step-by-step explanation:

(10 5/12) - (4 7/8) = (10 +5/12) -(4 +7/8)

... = (10 -4) +(5/12 -7/8)

... = 6 + (5/12 -7/8) . . . . . read on for how to simplify this

_____

<em>Adding fractions</em>

Adding fractions can be done in a mechanical sort of way using the formula ...

... a/b + c/d = (ad +bc)/(bd)

Here, we have a=5, b=12, c=-7, d=8, so the sum is ...

... (5·8 +12(-7))/(12·8) = (40 -84)/96 = -44/96

The numerator and denoinator of this fraction are both multiples of 4, so we can reduce the fraction.

... -44/96 = 4(-11)/(4·24) = -11/24

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<em>Back to the problem at hand</em>

... 6 + (5/12 -7/8) = 6 - 11/24

Now, we know that 1 = 24/24, so when we subtract 11/24 from 1, we get ...

... 1 - 11/24 = 24/24 - 11/24 = (24 -11)/24 = 13/24

So, our expression 6 - 11/24 can be rewritten as ...

... 6 -11/24 = (5 + 1) - 11/24 = 5 + (1 -11/24) = 5 13/24

Summary

... (10 5/12) - (4 7/8) = 5 13/24

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<em>Another way to add fractions</em>

The way to add fractions that is commonly taught is to first find a common denominator. Here that means you want to find the smallest number that is a multiple of both 12 and 8, the two denominators. You may recognize that number as being 24 = 12·2 = 3·8. (The methods of finding the common denominator (least common multiple) for numbers not in your memorized multiplication tables are not easy to describe.)

The next step in this method is to rewrite the fractions so they each have this denominator. The multipliers in the above equation are helpful for that purpose.

... 5/12 = (5·2)/(12·2) = 10/24

... 7/8 = (7·3)/(8·3) = 21/24

Now, the subtraction can proceed easilly:

... 10/24 - 21/24 = (10 -21)/24 = -11/24 . . . . . same result as above

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