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otez555 [7]
3 years ago
12

Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 mi/h slower than the other. If

the two jets are 2956 miles apart after two hours, what is the rate of change?
Mathematics
1 answer:
maw [93]3 years ago
4 0

Answer:

1478 mi/h  

Step-by-step explanation:

The rate of change is the distance divided by the time.

\text{Rate of change} = \dfrac{\text{distance}}{\text{time}} = \dfrac{\text{2956 mi}}{\text{2 h}} = \textbf{1478 mi/h}

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Step One

Find AM

Formula

AM = MN - AN

Givens

MN = 67.2

AN = 32

Solution

AM - 67,2 - 32

AM = 35.2

Step Two

Set up a solution

67.2/35.2 = 81.9/x            Cross Muliply

67.2 * x   =    81.9 * 35.2   Combine the right

67.2 * x = 2882.88            Divide by 67.2

x = 2882.88/67.2

x = 42.9                             Answer

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2 years ago
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Bond [772]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

7 0
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