Question

Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 mi/h slower than the other. If the two jets are 2956 miles apart after two hours, what is the rate of change?

Answer 1

Answer:

1478 mi/h  

Step-by-step explanation:

The rate of change is the distance divided by the time.

$\text{Rate of change} = \dfrac{\text{distance}}{\text{time}} = \dfrac{\text{2956 mi}}{\text{2 h}} = \textbf{1478 mi/h}$