Question

What is the distance between P(-4,3) and Q(6,1)? Round to the nearest tenth.

Answer 1

Answer:

The answer is

10.2 units

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} }$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(-4,3) and Q(6,1)

The distance between them is

$|PQ| = \sqrt{ ({ - 4 - 6})^{2} + ({3 - 1})^{2} } \\ = \sqrt{ ({ - 10})^{2} + {2}^{2} } \\ = \sqrt{100 + 4} \: \: \: \: \: \: \: \: \: \\ = \sqrt{104} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 2 \sqrt{26} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 10.1980390271$

We have the final answer as

10.2 units to the nearest tenth

Hope this helps you