To find the difference between these numbers you need to subtract 8.3 - 3.9
and that equals 4.4<span />
Answer:
x = -1/2 and -2
Step-by-step explanation:
Solve for <em>x</em>: Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Using the quadratic formula: Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
The function that represents the growth of this culture of bacteria as a function of time is; P = 1500e^(1.0986t)
<h3>How to calculate Exponential Growth?</h3>
The formula for exponential growth is;
P = P₀e^(rt)
where;
P = current population at time t
P₀ = starting population
r = rate of exponential growth/decay
t = time after start
Thus, from our question we have;
4500 = 1500 * e^(r * 1)
4500/1500 = e^r
e^r = 3
In 3 = r
r = 1.0986
Thus, the function that represents the growth of this culture of bacteria as a function of time is;
P = 1500e^(1.0986t)
For the culture to double, then;
P/P₀ = 2. Thus;
e^(1.0986t) = 2
In 2 = 1.0986t
t = 0.6931/1.0986
t = 0.631 hours
Read more about Exponential Growth at; brainly.com/question/27161222
#SPJ1
Answer:
a) Scores of 2 and higher are significantly high
b) Scores of -2 and lower are significantly low
c) Scores between -2 and 2 are not significant.
Step-by-step explanation:
Mean = 0
Standard deviation = 1
a. significantly high (or at least 2 standard deviations above the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
So scores of 2 and higher are significantly high
b. significantly low (or at least 2 standard deviations below the mean).
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores of -2 and lower are significantly low
c. not significant (or less than 2 standard deviations away from the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores between -2 and 2 are not significant.
1. 6.73 x 10^6
2. 1.33 x 10^4
3.9.77 x 10^22
4. 3.84 x 10^5
The rest i didn’t understand what where you trying to say
