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forsale [732]
3 years ago
8

Can someone please help me I’m stuck I don’t know

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0

Answer:

140

Step-by-step explanation:

Because the lines are parallel:

\dfrac{DE}{35}=\dfrac{60}{15} \\\\DE=4\cdot 35=140

Hope this helps!

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(x+3)(x-5)= in standard form
sammy [17]
Answer:

x^2-2x-15

Hope this helps!
5 0
3 years ago
Read 2 more answers
HELP Use either law of sines or law of cosine. Need help on this problem! show work please!​
Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

4 0
3 years ago
Read 2 more answers
The first 5 terms of a sequence are shown below:
nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

T_2-T_1 \\  - 2 - 3 \\  =  - 5

Common ratio =

T_2/T_1 \\  \frac{ - 2}{3}

The common difference applies to the other given numbers for example :

T_3- T_2  =  - 7 - ( - 2) \\  =  - 7 + 2 =  - 5

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0
3 years ago
Norm has $15,000 to deposit. His daughter is a junior in high school and plans to go to college. Recommend the best way for Norm
galina1969 [7]

Answer:

A money market account paying 3.5% interest, renewable for three-month commitments.

6 0
3 years ago
Read 2 more answers
14% of 980?
Natasha2012 [34]
137.2
30
$298.30
390
5970
3050
16
150
5500000
8 0
3 years ago
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