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marysya [2.9K]
2 years ago
7

Tanner is installing a new door and knows that the length of the door is 10 inches less than three times the width. Select the e

quation that could be used to determine the area of the outward facing side of the door. Recall that the formula for the area of a rectangle is A = l · w, where l represents the length, and w represents the width.
Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0

A = 3w^2 - 10w

That's the plato answer

arsen [322]2 years ago
5 0

Answer:

l = 3w-10

Step-by-step explanation:

the length is ten inches less than three times the width

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kramer

Answer:

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Step-by-step explanation:

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2 years ago
Why do a cars tires need more air in the winter than they do in the summer
kodGreya [7K]
I believe the pressure inside the tires decreases in the winter because of the cold and increases in the summer when the air is heated up making it expand and add more pressure
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3 years ago
Read 2 more answers
The perimeter of a rectangle is 32 centimeters. the width is 7 centimeters.
Ilia_Sergeevich [38]
I hope this helps you

7 0
3 years ago
What is an equation in slope-intercept form of the line that passes through the points (−2, −2) and (1, 7)? A.y = 4x + 3 B.y − 7
antoniya [11.8K]

Answer:

C.y = 3x + 4

Step-by-step explanation:

We have two points, so we can find the slope

m = (y2-y1)/ (x2-x1)

   = (7--2)/ (1--2)

   = (7+2)/(1+2)

    = 9/3

    =3

The slope is 3

We can find the point slope form of the line

y-y1 = m(x-x1)

y-7 = 3(x-1)

Distribute

y-7 =3x-3

Add 7 to each side

y-7+7 = 3x-3+7

y = 3x+4

This is in slope intercept form (y=mx+b)

8 0
3 years ago
Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3
FromTheMoon [43]

Answer:

D=\sqrt{(147-30\sqrt{10}}

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\

Hence this is our answer

6 0
3 years ago
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