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3 years ago

PLEASE HELP AND SIMPLIFY YOUR ANSWER

Mathematics

1 answer:

Alex Ar [27]3 years ago

8 0

Area of a triangle is 1/2 of base *height
A=1/2 *10 and 6/7 *9 and 3/8
break the whole numbers: 1/2 *76/7 * 75/8 =1425/28
write it into mixed number:50 and 25/28

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Solve the system of linear equations. separate the x- and y- values with a coma.

kobusy [5.1K]

Solve the following system:
{7 x - 3 y = 37 | (equation 1)
{14 x + 11 y = 23 | (equation 2)
Swap equation 1 with equation 2:
{14 x + 11 y = 23 | (equation 1)
{7 x - 3 y = 37 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x + 11 y = 23 | (equation 1)
{0 x - (17 y)/2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:
{14 x + 11 y = 23 | (equation 1)
{0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:
{14 x + 11 y = 23 | (equation 1)
{0 x+y = -3 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{14 x+0 y = 56 | (equation 1)
{0 x+y = -3 | (equation 2)

Divide equation 1 by 14:
{x+0 y = 4 | (equation 1)
{0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 4
{y = -3

4 0

3 years ago

The perimeter of a rectangle is 128 cm, and the ratio of its sides is 5: 3. Find the area of a rectangle

blondinia [14]

Answer:

Area of the rectangle = $15 cm^2$

Step-by-step explanation:

Perimeter of the rectangle= 128 cm

Ratio of length to width is:

$\frac{Length}{Width}= \frac{5}{3} \\\\Length=5 cm\\\\Width=3 cm$

Area of the rectangle= Length*Width

$=5cm*3cm\\\\=15cm^2$

Area of the rectangle = $15 cm^2$

7 0

4 years ago

Read 2 more answers

a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora

Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is $6x+y=3500$ ..........[1]

When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is $4x+y=2400$ ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

$6x+y-4x-y=3500-2400$

$2x=1100$

$x=550$

Put value in [1],

$6(550)+y=3500$

$3300+y=3500$

$y=200$

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

8 0

4 years ago

A: 5x − 2y = 10

Nuetrik [128]

Answer:

D) Multiply A by -4 and B by 5

Step-by-step explanation:

5x-2y=10

4x+3y=7

----------------

-4(5x-2y)=-4(10)

5(4x+3y)=5(7)

----------------------

-20x+8y=-40

20x+15y=35

---------------------

23y=-5

y=-5/23

5x-2(-5/23)=10

5x+10/23=10

5x=10-10/23

5x=230/23-10/23

5x=220/23

x=(220/23)/5

x=(220/23)(1/5)

x=220/115

x=44/23

7 0

4 years ago

What is the value of largest integers x such that 112/2^x is an integer.

Gennadij [26K]

Answer:

x = 4

Step-by-step explanation:

16 × 7 = 112

2^4 = 16

so that is the answer

6 0

3 years ago