Answer:
Heterozygous is the answer
Answer:
After every 0.192 centimorgan
Explanation:
If there are 125 million base pairs then according to the parallel ratio compare rule it should contain an average of 650 genes. If every gene has to be marked by a single marker on each end then a total number of 651 markers are used after every 0.192 centimorgan distance.
Answer. They are the “last trophic level” in some hierarchies because they feed on everything (National Geographic). However, according to the strict trophic level definition they would be primary consumers.
Answer:
a) HT
Explanation:
This question shows an animal with two distinct unlinked genes i.e. on different chromosomes. One gene codes for head shape and the other for tail length. The gene for head shape possess alleles H and h, while gene for tail length possess alleles T and t.
According to Mendel's law of independent assortment, the alleles of a gene will separate into gametes independently of the alleles of another gene. This occurs in such a way that each gamete will contain only one allele from a gene.
Based on this principle, an animal with genotype HhTt will undergo meiosis and randomly produce gametes with the following allelic combinations: HT, Ht, hT, and ht. As seen in the gametes, only one allele of a gene occured in a gamete at a time.
Therefore, HT is the genotype possible in a gamete of parent: HhTt.
Answer:
Nobody shall ever know -.-
Explanation:
