The hypothetical cell will approximately contain 94 percent (94%) of water.
- If a cell is placed in a hypertonic solution that contains more concentration of solutes (such as salt and glucose) than the cell, then it will shrink because water moves outside the cell.
- If a cell is placed in a hypotonic solution that contains more concentration of water than the cell, then the water will move inside the cell.
- Finally, if a cell is placed in an isotonic solution, which contains the same concentration of solute and solvent as outside the cell, there will be no change in the cell and the solution.
- In this case, the percentage of solutes is equal to 5% (glucose) + 1% (salt) = 6%, so the remmaining porcentage of water is equal to 94 percent (94%).
Learn more in:
brainly.com/question/3568318?referrer=searchResults
<span>it probably break apart with cleavage, because the carbon atoms in graphite from sheets that could split apart easily in layers.</span>
<span>the tidal mouth of a large river, where the tide meets the stream.</span>
Answer:
The resting membrane potential is created and maintained due to the difference in the total charge or ions present outside and inside of the cell. The resting membrane potential depolarize if sodium come in and and potassium leaves the cell.
Explanation:
The resting membrane is maintained and created by the distribution of potassium and sodium ions. The membrane potential of a resting cell is -70mV (negative) because more sodium ions is present outside the cell than the potassium ions present inside the cell.
When the sodium ions enter inside the cell and potassium ions move outside the cell, the inside of the cell becomes more positive as compared to the outside and the membrane potential changes from -70 mV to +30 mV. The cells will depolarize due to the accumulation of sodium ions inside the cell.
