3 years ago

The coordinates below represent two linear equations.

1 answer:

7 0

Hello,
Answer A: no solution

line 1: (-6,3), (3,6)==>y-3=(x+6)*3/9==>x-3y=-15 (1)
line 2: (-3,1), (3,3)==>y-1=(x+3)2/6==> x-3y=-6 (2)

(1)-(2)==>0x=-9 ==> no solution
line 1 // line 2

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Create the equation of a line that is perpendicular to 2y=14+(2/3) x and passes through the point (-2,8).

anzhelika [568]

Answer:

y = -3x +2

Step-by-step explanation:

If you divide the equation for the given line by 2, it will be in slope-intercept form:

y = (1/3)x +7

This tells you its slope is 1/3. The slope of the perpendicular line is the negative reciprocal of this: -1/(1/3) = -3. The point-slope form of the equation for the perpendicular line can be written as ...

y = m(x -h) +k . . . . . line with slope m through point (h, k)

Your line is ...

y = -3(x -(-2)) +8

y = -3x +2