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3 years ago

The coordinates below represent two linear equations.

1 answer:

7 0

Hello,
Answer A: no solution

line 1: (-6,3), (3,6)==>y-3=(x+6)*3/9==>x-3y=-15 (1)
line 2: (-3,1), (3,3)==>y-1=(x+3)2/6==> x-3y=-6 (2)

(1)-(2)==>0x=-9 ==> no solution
line 1 // line 2

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Morgarella [4.7K]

Answer:

X = 10

Step-by-step explanation:

8 0

4 years ago

Pls help ! i dont understand how to solve this

Mazyrski [523]

Answer:

answer is 4

Step-by-step explanation:

we need to find the width of the larger rectangle: 100/20=5

and then find the scale between them

20/4=5

and use the width to divide by that, and you will get the width for the smaller shape, which is 5/5=1

1*4=4

4 0

3 years ago

Simplify the expression. 64 7/12<br> 16<br> 8 √2<br> 4√2<br> 32

mezya [45]

Answer:

$8\sqrt2$

Second option is correct.

Step-by-step explanation:

We have been given the expression $(64)^{\frac{7}{12}}$

We can write the term 64 as $64=2^6$

Thus, we have

$(2^6)^{\frac{7}{12}}$

Now, use the exponent law $(x^m)^n=x^{mn}$

$(2)^{6\cdot\frac{7}{12}}$

On simplifying, we get

$(2)^{\frac{7}{2}}$

This expression can be further simplified as

$\sqrt{2^7}\\\\=\sqrt{2^6\cdot2}\\\\=2^3\sqrt{2}\\\\=8\sqrt2$

Second option is correct.

8 0

3 years ago

Plz help i beg!! 50 points

dedylja [7]

Answer:

63.25 sq. ft

Step-by-step explanation:

the area of fig. =

(½×8×6)+(½×3.14×5²)

= 24 + 39.25

= 63.25 sq. ft

5 0

3 years ago

Read 2 more answers

If T is the centroid of ∡MNP, TN = 16, MQ = 23, and RP = 18, find each missing measure.

kramer

Answer:

a) QT = 8

b) QN = 24

c) QP = 23

d) MP = 46

e) RT = 6

f) TP = 12

Step-by-step explanation:

Find the diagram attached

If T is the centroid of<MNP, then the following are true;

TN = 2QT

Given TN = 16

16 = 2QT

QT = 16/2

QT = 8

QN = QT + TN

QN = 8 + 16

QN = 24

MQ + QP = MP and MQ = QP

If MQ = 23

QP = 23

Recall that MP = MQ + QP

MP = MQ + MQ

MP = 2MQ

MP = 2(23)

MP = 46

Similarly, TP = 2RT

RT = TP/2

Also RP = RT + TP

RP = RT + 2 RT

RP = 3RT

18 = 3RT

RT = 18/3

RT = 6

Recall that TP = 2RT

TP = 2(6)

TP = 12

3 0

3 years ago