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3 years ago

12

A bank offers a 3% annual interest rate for a savings account. Hannah puts $6,000 into an account to save for college. How much

will be in the account after a year?

1 answer:

Cloud [144]3 years ago

8 0

(103/100)×6000
=¢6180

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A jewelry box is in the shape of a rectangular with a volume of 528 cubic inches l. The length of the box is 12 inches and the h

Artist 52 [7]

Volume=length*height*width
528=12*5.5*w

divide both sides by 12
44=5.5w
divide both sides by 5.5
8=w
width is 8 inches

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2 years ago

On September 4, Nita Darmati signed a $5,350 promissory note to purchase furniture for her home office. The note had a simple in

snow_lady [41]

The maturity value is the principal value together with interest due.
.. mv = P +Prt
.. = 5350*(1 +0.085*120/360) . . . . . . year is 360 days for "ordinary interest"
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The maturity value is $5501.58.

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3 years ago

Write the slip-intercept form of the equation of the line described

kompoz [17]

Answer:

1) y=⅚x -2⅓

2) y=8/3x -5

Step-by-step explanation:

<u>Point-slope form:</u>

y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient.

Gradient of given line= $\frac{5}{6}$

Thus, m=⅚

Susbt. m=⅚ into the equation,

y= ⅚x +c

Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.

When x=4, y=1,

1= ⅚(4) +c

$1 = \frac{20}{6} + c \\ c = 1 - \frac{20}{6} \\ c = 1 - 3 \frac{1}{3} \\ c = - 2 \frac{1}{3}$

Thus the equation of the line is $y = \frac{5}{6} x - 2 \frac{1}{3}$ .

The gradients of perpendicular lines= -1.

Gradient of given line= -⅜

-⅜(gradient of line)= -1

gradient of line

= -1 ÷ (-⅜)

= -1 ×(-8/3)

= $\frac{8}{3}$

$y = \frac{8}{3} x + c$

When x=3, y=3,

$3 = \frac{8}{3} (3) + c \\ 3 = 8 + c \\ c = 3 - 8 \\ c = - 5$

Thus the equation of the line is $y = \frac{8}{3} x - 5$ .

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2 years ago

Brainly: This is for math.<br> Me: Nah Faam

Korvikt [17]

Answer:

I know brainly is not the place to go for math

Step-by-step explanation:

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3 years ago

Can two lines be drawn from a point not on a line that will meet the line at a right angle? at a 45° angle? explain each answer.

vichka [17]

I believe the the correct answer would be yes. Two lines can be drawn from a point that is not collinear with a certain line that will meet the line at a right angle or 90 degree angle and at an angle of 45 degrees. We can freely draw any line that would pass through a given point and would cross a given line at any direction giving us different angles and this would include a 90 and 45 degree angle.

5 0

2 years ago