The Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.
Answer: 6.77*1022 Molecules
Explanation: :)
Answer:
Explanation:
Well the gas is the fuel for the flame of course. The collision theory comes into play when the gas turns on, chemicals collide with one another. Then reactions occur causing the flame. Then when you take away the fuel, the flame stops because there is no atoms or molecules to come together/collide with one another.
Sorry if its wrong or doesn't make sense... Wish you the best of luck on whatever your doing!
Answer:
0.97 atm.
Explanation:
From the question given above, the following data were obtained:
Final pressure (P2) = 6.8 atm
Initial temperature (T1) = 40 K
Final temperature (T2) = 280 K
Initial pressure (P1) =?
Thus, we can obtain the initial (original) pressure of the gas as follow:
P1/T1 = P2/T2
P1 /40 = 6.8/280
Cross multiply
P1 × 280 = 40 × 6.8
P1 × 280 = 272
Divide both side by 280
P1 = 272/280
P1 = 0.97 atm
Therefore, the original pressure of the gas is 0.97 atm.
Answer:
d. 60.8 L
Explanation:
Step 1: Given data
- Heat absorbed (Q): 53.1 J
- External pressure (P): 0.677 atm
- Final volume (V2): 63.2 L
- Change in the internal energy (ΔU): -108.3 J
Step 2: Calculate the work (W) done by the system
We will use the following expression.
ΔU = Q + W
W = ΔU - Q
W = -108.3 J - 53.1 J = -161.4 J
Step 3: Convert W to atm.L
We will use the conversion factor 1 atm.L = 101.325 J.
-161.4 J × 1 atm.L/101.325 J = -1.593 atm.L
Step 4: Calculate the initial volume
First, we will use the following expression.
W = - P × ΔV
ΔV = - W / P
ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L
The initial volume is:
V2 = V1 + ΔV
V1 = V2 - ΔV
V1 = 63.2 L - 2.35 L = 60.8 L