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3 years ago

What are empirical observations?

Chemistry

2 answers:

Nady [450]3 years ago

8 0

Answer:

Empirical evidence for a proposition is evidence, i.e. what supports or counters this proposition, that is constituted by or accessible to sense experience or experimental procedure. Empirical evidence is of central importance to the sciences and plays a role in various other fields, like epistemology and law.

Explanation:

thanks me later

aleksandrvk [35]3 years ago

6 0

Derived from experience or experiment. 2. depending upon experience or observation alone, without using scientific method or theory, esp. in medicine.

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3 years ago

How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K?

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3 years ago

What is the mass present in a 10.0L container of oxygen at a pressure of 105kPa and 20 degrees Celsius

omeli [17]

1.31 × 10⁴ grams.

<h3>Explanation</h3>

Assume that oxygen acts like an ideal gas. In other words, assume that the oxygen here satisfies the ideal gas law:

$P \cdot V = n \cdot R\cdot T$ ,

where

$P$ the pressure on the gas, $\bf P = 10^{5}\;\textbf{kPa}=10^{8}\;\textbf{Pa}$ ;
$V$ the volume of the gas, $V = 10.0 \;\text{L} = 10.0\times 10^{-3}\;\text{m}^{3}=10^{-2}\;\text{m}^{3}$ ;
$n$ the number of moles of the gas, which needs to be found;
$T$ the absolute temperature of the gas, $T=20\;\textdegree{}\text{C} = (20 + 273.15)\;\text{K} = 293.15\;\text{K}$ .
$R$ the ideal gas constant, $R = 8.314$ if P, V, and T are in their corresponding SI units: Pa, m³, and K.

Apply the ideal gas law to find $n$ :

$n = \dfrac{P\cdot V}{R\cdot T} = \dfrac{{\bf 10^{8}\;\textbf{Pa}}\times 10^{-2}\;\text{m}^{3}}{8.314 \;\text{Pa}\cdot\text{m}^{3}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}\times 293.15\;\text{K}} = 410.3\;\text{mol}$ .

In other words, there are 410.3 moles of O₂ molecules in that container.

There are two oxygen atoms in each O₂ molecules. The mass of mole of O₂ molecules will be ${\bf 2}\times 16.00 = 32.00\;\text{g}$ . The mass of 410.3 moles of O₂ will be:

$410.3 \times 32.00 = 1.31\times10^{4}\;\text{g}$ .

What would be the mass of oxygen in the container if the pressure is approximately the same as STP at $10^{5}\;\textbf{Pa}$ or $10^{2}\;\text{kPa}$ instead?

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4 years ago

The mass spectrum represented above is most consistent with which of the following elements? Eu Gd Tb Dy

Kryger [21]

Answer:

The mass spectroscopy is most consistent with the element Gd

Explanation:

Here we have the average atomic mass given by the weighted average found by multiplying the abundance in nature of the various isotopes by their observed atomic masses followed by the summation of the multiplication results as follows;

Based on approximate measurement of the chart, we have the values for the relative abundance given as follows;

Isotope, I Relative abundance, A I×A

154 1 154

155 6 930

156 8 1248

157 6.2 973.4

158 10 1580

160 8.5 1360

Sum 39.7 6245.5

Average atomic mass = 6245.5/39.7 = 157.314 atomic mass unit

Atomic mass of Eu = 151.964 u

Atomic mass of Gd = 157.25 u

Atomic mass of Tb = 158.92535 u

Atomic mass of Dy = 162.5 u

Therefore, the mass spectroscopy is most consistent with the element Gd.

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4 years ago