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3 years ago

PLEASE HELP ASAP!!!

Chemistry

2 answers:

alexdok [17]3 years ago

8 0

Answer:

Answers are bellow.

Explanation:

The element with electron configuration 1s22s22p63s1 belong I A group in the periodic table and it is sodium because it loses one electron.

We have periodic table in attachments.

Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table, because it has a single electron in its outer shell, which it readily donates, creating a positively charged ion—the Na+ cation. Its only stable isotope is 23Na.

The free metal does not occur in nature, and must be prepared from compounds.

It is soft metal, reactive and with a low melting point.

AveGali [126]3 years ago

5 0

Answer:

Explanation:

The vertical columns of the periodic table are known as groups, while the horizontal rows of the periodic table are called periods. All the elements that belong to a group have the same valence, and therefore, they have characteristics or properties similar to each other. That is, in each group the elements with the same number of electrons appear in the last occupied level or valence shell. For example, all elements in group 13 contain 3 electrons in their outermost shell.

On the other hand, in each period the elements appear whose last level of their electronic configuration coincides with the number of the period. For example, period 3 includes elements whose outermost electrons are at level 3.

So, in this case the element belongs to period 3 and group 1. When locating it in the periodic table, the element is sodium (Na).

The alkali metals correspond to Group 1 of the Periodic Table. So sodium is an alkali metal. It is characterized by its high reactivity, due to the fact that they form chemical bonds with many types of substances and elements and that they do it easily. This is due to its high electronegativity and the ease of releasing its electron from the outermost layer.

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nikitadnepr [17]

Answer:

There are approximately $0.271\; \rm mol$ of formula units in that $\rm 15.2\; g$ of $\rm KOH$ (the solute of this solution.)

Explanation:

A solution includes two substances: the solute and the solvent. Note the solution here contains significantly more water than $\rm KOH$ . Hence, assume that water is the solvent (as it is in many other solutions.)

The (molar) formula mass of $\rm KOH$ is necessary for finding the number of moles of

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$\rm O$ : $15.999$ .
$\rm H$ : $1.008$ .

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$\begin{aligned}& M(\mathrm{KOH}) \\ &\approx 39.098 + 15.999 + 1.008 \\ &= 56.105\; \rm g \cdot mol^{-1}\end{aligned}$ .

The number of moles of $\rm KOH$ formula units in this $15.2\; \rm g$ sample would be:

$\begin{aligned}n &= \frac{m(\mathrm{KOH})}{M(\mathrm{KOH})} \\ &\approx \frac{15.2\; \rm g}{56.105\; \rm g \cdot mol^{-1}} \approx 0.271\; \rm mol \end{aligned}$ .

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