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3 years ago

Solve the formula for the specified variable. g=th for t T=?

Mathematics

2 answers:

dexar [7]3 years ago

8 0

Answer:

Step-by-step explanation:

g=th

g/h=t

Sidana [21]3 years ago

4 0

Hope this helps
You have to rearrange the formula

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The measure of an angle is 12°. What is the measure of its supplement? *No answer just number*

Elena-2011 [213]

Answer:

168°

Step-by-step explanation:

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3 years ago

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How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of $\frac{5}{6}$ kilogram of candy is $7.5

- We need to find the cost of $4\frac{5}{7}$ kilogram

We can use the ratio to find the answer

======= Dollar : Kilogram

======= 7.5 : $\frac{5}{6}$

======= c : $4\frac{5}{7}$

By using cross multiplication

∴ c × $\frac{5}{6}$ = 7.5 × $4\frac{5}{7}$

∵ $4\frac{5}{7}$ = $\frac{4*7+5}{7}$

∴ $4\frac{5}{7}$ = $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = 7.5 × $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = $\frac{495}{14}$

Divide both sides by $\frac{5}{6}$

∴ c = $\frac{495}{14}$ ÷ $\frac{5}{6}$

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = $\frac{495}{14}$ × $\frac{6}{5}$

∴ c = $\frac{297}{7}$ = 42.43 dollars

∵ c represents the cost of $4\frac{5}{7}$ kg

∴ It costs $42.43

7 0

3 years ago

HELP please! ‍♂️ Last one is 0.5 < x < 1.5 And none

Ket [755]

1.5 is lesser than 0.5. Oh, wait nevermind I meant to say -1.5 is lesser than 0.5

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3 years ago

Ethan invests $3000 in a mutual fund that earns 6% interest per year compounded monthly. After 10 years, the investment is worth

sladkih [1.3K]

Answer:

$A = P(1 +\frac{r}{n} )^{nt}$

A = 3000(1 + .06/12)^120

strange the question did not want you to calculate the amount

that was given....

the interest is 5,458.19 - 3000 = 2,458.19

Step-by-step explanation:

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3 years ago

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Lostsunrise [7]

Answer:

the height of the object is and the height at 6 seconds is .

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c. -16(t - 9) (t +4)

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3 years ago