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vladimir2022 [97]

3 years ago

9

A cartoon plane with four engines can accelerate at 8.9 meters per second squared

1 answer:

Tom [10]3 years ago

4 0

The answer is 2728283 69

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What mass of whole blood (in kg) can be contained in a plastic container whose dimensions are 125 mm by 110 mm by 35 mm? See cha

irakobra [83]

The mass of whole blood is 0.51 kg.

Given data:

The dimensions of container is 125 mmx 110 mm x 35 mm.

From the chart, the density of whole blood at 37 C is,

$\rho=\frac{1060kg}{m^3}$

The volume of container can be calculated as,

$\begin{gathered} V=125mm\times110mm\times35mm \\ V=481250mm^3\times\frac{1m^3}{10^{-9}mm^3} \\ V=4.8125\times10^{-4}m^3 \end{gathered}$

The mass of whole blood will be,

$\begin{gathered} \rho=\frac{m}{V} \\ \frac{1060kg}{m^3}=\frac{m}{4.8125\times10^{-4}m^3} \\ m=0.51kg \end{gathered}$

Thus, the mass of whole blood is 0.51 kg.

4 0

1 year ago

A capacitor has a charge of 4.6 Î¼C. An E-field of 1.8 kV/mm is desired between the plates. There's no dielectric. What must be

Scrat [10]

Answer:

$A = 0.2875 m^2$

Explanation:

As we know that

$Q = 4.6 \mu C$

E = 1.8 kV/mm

now we know that electric field between the plated of capacitor is given as

$E = \frac{\sigma}{\epsilon_0}$

now we will have

$1.8 \times 10^6 = \frac{\sigma}{\epsilon_0}$

$\sigma = (1.8 \times 10^6)(8.85 \times 10^{-12})$

$\sigma = 1.6 \times 10^{-5} C/m^2$

now we have

$\sigma = \frac{Q}{A}$

now we have area of the plates of capacitor

$A = \frac{Q}{\sigma}$

$A = \frac{4.6 \times 10^{-6}}{1.6 \times 10^{-5}}$

$A = 0.2875 m^2$

5 0

3 years ago

A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 523 Hz and has a spe

Firdavs [7]

To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

It can be described as

$f = \frac{c\pm v_r}{c\pm v_s}f_0$

c = Propagation speed of waves in the medium

$v_r$ = Speed of the receiver relative to the medium

$v_s$ = Speed of the source relative to the medium

$f_0 =$ Frequency emited by the source

The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

$v_s = 32.2m/s \rightarrow$ Velocity of car

$v_r = 14.8 m/s \rightarrow$ velocity of motor

$c = 343m/s \rightarrow$ Velocity of sound

$f_0 = 523Hz \rightarrow$ Frequency emited by the source

Replacing we have that

$f = \frac{c + v_r}{c - v_s}f_0$

$f = \frac{343 + 14.8}{343 - 32}(523)$

$f = 601.7Hz$

Therefore the frequency that hear the motorcyclist is 601.7Hz

8 0

4 years ago

If a force of 32000N exerted pressure of 160N/m² , find the area on which the force acts.

Alex17521 [72]

Answer: 200m^2

Explanation:

160N=32000N/x

x*160N=32000

x=200m^2

4 0

2 years ago

ball A of mass 5.0 kg moving at 20 meters per second collides with ball B of unknown mass moving at 10. meters per second in the

antiseptic1488 [7]

Answer:The mass of ball B is 10 kg.

Explanation;

Mass of ball A = $M_A=5 kg$

Velocity of the ball A before collision: $U_A=20 m/s$

Velocity of ball A after collision= $V_A=10 m/s$

Mass of ball B= $M_B$

Velocity of the ball B before collision: $U_B=10 m/s$

Velocity of ball B after collision= $V_B=15 m/s$

$M_AV_A+M_BV_B=M_AU_A+M_BU_B$

$5 kg\times 10 m/s+M_B\times 15=5 kg\times 20m/s+M_B\times 10m/s$

$M_B=10kg$

The mass of ball B is 10 kg.

8 0

3 years ago