Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water
Answer:
W'=125.44 N
Explanation:
The weight of a person on the surface of Earth is 784 N
Weight is given by :
W = mg
m is mass of the person and g is acceleration due to gravity on the surface of Earth (10 m/s²)
The acceleration due to gravity on the surface of Moon, g' = 1.6 m/s²
Weight of the person on the moon is :
W'=mg'
Hence, the person would weigh 125.44 N on the Moon.
You cant because zero is pretty much a non existent number that if you were to divide it by any number, zero would fit into that number intinity times...(it pretty much wont reach that number) so you cant for eg(how many 'nothings' fit into this box)
