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DaniilM [7]
3 years ago
15

a major difference radio waves, visible light, and gamma rays is the _________ of the photons, which results in different photon

frequencies and wavelengths
Physics
2 answers:
Aleks04 [339]3 years ago
3 0

There is a spectrum of electromagnetic radiation with variable wavelengths and frequency, which in turn imparts different characteristics. ... X-rays and gamma rays have the same nature as visible light, radiant heat, and radio waves; however, they have shorter wavelengths and consequently a larger photon energy.

Aleks04 [339]3 years ago
3 0

Answer:

Energy APEX Verified

Explanation:

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You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

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3 years ago
What is the difference between a low tide and a high tide
Savatey [412]
A high tide means when the water has risen and is higher up(closer to high up land). Low tide is when it’s receded
6 0
3 years ago
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A 250KG ROCKET HAS 1,953,125 JOULES OF ENERGY. HOW FAST IS IT<br>MOVING?​
UNO [17]

Answer:

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Explanation:

6 0
4 years ago
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
How is your guys day going?​
faltersainse [42]
Good i’m tired how about you
4 0
3 years ago
Read 2 more answers
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