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vladimir1956 [14]

3 years ago

9

A sound wave produced by a clock chime is heard 400 m away 2.0 s later. The sound wave has a frequency of 512 Hz. What is its pe

riod?

1 answer:

emmasim [6.3K]3 years ago

3 0

Answer:

$\frac{1}{512}$ seconds

Explanation:

T = 1 / f

where T is the period and f is frequency.

Here the frequency is 512 Hz.

<em>Using the formula:</em>

T = $\frac{1}{512}$ seconds

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A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 11.5 m/s and accelerates

elena-14-01-66 [18.8K]

Answer:

given,

initial velocity = 11.5 m/s

acceleration = 0.5 m/s²

time = 7 s

a) using equation of motion

v = u + a t

v = 11.5 + 0.5 × 7

v = 15 m/s

b) $s = u t + \dfrac{1}{2}at^2$

$s = 11.5\times 7 + \dfrac{1}{2}\times 0.5\times 7^2$

s = 92.75 m

distance traveled by racer with final velocity

d = 300 - 92.75

= 207.25 m

time spend to travel 207.25

$t = \dfrac{207.25}{15}$

t = 13.82 s

total time spent to travel 300m

t = 7 + 13.82

t = 20.82 s

time required to travel 300 m with initial velocity

$t_0 =\dfrac{d}{v_0}$

$t_0 =\dfrac{300}{11.5}$

= 26.09 s

time saved due to acceleration

t = 26.09 - 20.82 = 5.27 s

c) second racer is 5 m apart from the first one

distance traveled by the second racer till first one finishes the race

$d_2 = v_2t$

$d_2 = 11.8\times 20.82 = 245.676 m$

distance behind the leader

d = 300 -5 -245.676 = 49.34 m

time behind the winner

$t_f = \dfrac{d}{v_2} =\dfrac{49.34}{11.8} = 4.18 s$

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3 years ago

Which single force acts on an object in freefall?

nirvana33 [79]

Gravity i think but if uts not gravity then it will be air resistance

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Igoryamba

> Non-zero numbers (like 1,2,3,4...) are always significant
> A zero sandwiched between two non-zero numbers is always significant
> Trailing zeros in a decimal (not whole number like million) are always significant.

<span>0,020170 = 2.0170 × 10^-2

5 sig-figs
</span>

4 0

3 years ago

Violet light (λ = 400 nm) passing through a diffraction grating for which the slit spacing is 6.0 μm forms a pattern on a screen

sergey [27]

Answer:

3 order dark fringe

Explanation:

y = Distance from central bright fringe = 204 mm

λ = Wavelength = 400 nm

L = Distance between screen and source = 1 m

d = Slit distance = 6 μm

$tan\theta =\frac{y}{L}\\\Rightarrow tan\theta =\frac{204}{1000}=0.2012^{\circ}$

$dsin\theta=m\lambda\\\Rightarrow m=\frac{dsin\theta}{\lambda}\\\Rightarrow m=\frac{6\times 10^{-6}sin0.2012}{400\times 10^{-9}}=2.9982\approx 3$

Order of fringe is 3

So, it is a Dark order fringe

3 0

4 years ago