Answer:
The equation that will express this result os
h = 0 = vy t - 1/2 g t^2 so the net height traveled by the bullet is zero
vy t = 1/2 g t^2
vy = 1/2 g t
vy = 1/2 * 9.8 * t you could use -9.8 to indicate vy and g are in different directions
tx = sx/ vx = 46.4 / 471 = .0985 sec time to travel up and down to original height
th = .0985 / 2 = .0493 sec time to reach maximum height
vy = g ty = 9.8 * .0493 sec = .483 m/s initial vertical speed
Sy = vy t - 1/2 g t^2 = .483 * .0493 - 1.2 9.8 (.0493^^2)
Sy = .0238 - 4.9 ( .0493)^2 = .0238 - .0119 = .0119 m
Height to which bullet will rise - if the gun is aimed at this height then in .0985 seconds the bullet will fall to zero height
Check: .483 / 9.8 = .0493 time to reach zero vertical speed
total travel time = 2 * .0493 = .0986 sec
471 * .0986 = 46.4 m total distance traveled by bullet
Answer:
m = 0.59 kg.
Explanation:
First, we need to find the relation between the frequency and mass on a spring.
The Hooke's law states that
And Newton's Second Law also states that
Combining two equations yields
The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.
And given that ω = 2πf
the relation between frequency and mass becomes
.
Let's apply this to the variables in the question.
Answer:
when the radius is halved, F becomes 4 times
Explanation:
<u><em>The formula is given by</em></u>
<u><em>When r is halved:</em></u>
=> 
=> 
<u><em>This means when the radius is halved, F becomes 4 times</em></u>
So this is dealing with the conservation of energy. So you set kinetic energy equal to potential energy, so it looks like this:
1/2mv^2=mgh. The m's cancel out, so it is 1/2v^2=gh.
To find out what the height h is, divide g on both sides, so...
h=0.5v^2/g. v=22m/s, g=9.81m/s^2, so h=(0.5)(22^2)/(9.81)=24.67m
I think its the last one, a student slips on the ice in front of school and sprains his ankle. An example of a natural fiber could be cotton B.
