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4 years ago

Solve for x. 2x + 9 = 33 What is the answer? A 7.5 B 12 C 21 D 84

2 answers:

8 0

B, because you subtract 9 from both sides(2x-9 leaves 2x by itself then 33-9=24), which leaves you with 2x=24 the you divide everything by 2 which leaves you with x=12

finlep [7]4 years ago

7 0

Answer:

b 12

Step-by-step explanation:

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NO LINKS OR FILES ONLY ANSWER IF YOU KNOW IT PLEASE

agasfer [191]

Answer:

Step-by-step explanation:

100% is the whole graph so 23% of 100 is 23

5 0

3 years ago

Adding negative numbers<br> Add.<br> -3+ (-2) =

djyliett [7]

Answer:

-5

Step-by-step explanation:

its the same as adding positive numbers but with a minus sign so -3+(-2)= -5

7 0

3 years ago

Read 2 more answers

A student used the graph below to identify the minimum/maximum. The student said the graph had a maximum of 1. Explain the stude

11Alexandr11 [23.1K]

Answer: Answer is in the step.

Step-by-step explanation:

The student made a mistake by identifying the maximum point by the x coordinate value of the vertex. Minimum or maximum points are determine using the y coordinate value.The student can determine the difference between a maximum and minimum by identifying the y coordinate of the vertex.

7 0

3 years ago

Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ

liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

$\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy$

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

Mx(x,y) = d/dx 8x²y = 16xy
Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy$

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2$

We conclude that the line integral is 1/2

4 0

3 years ago

Find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5.

Gnesinka [82]

We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3

4 0

4 years ago