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Marysya12 [62]
2 years ago
15

Raymond earns 1795 each month and pays 53.40 on electricity to nearest 10th of a percent what percent of Raymonds earnings are s

pent on electricity each month
Mathematics
1 answer:
kogti [31]2 years ago
7 0
3.1% of Raymond’s salary
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one-third of a number x is equal to 22 less than the number. Write and solve an equation to find the number.
vitfil [10]
1/3x=x-22
Add 22 to both sides to get 22+1/3x=x
Subtract 1/3x from both sides to get 22=2/3x
Multiply each side by 3/2 to get x=33!
4 0
3 years ago
What two numbers multiply to get 40 and add to get 11
Trava [24]
I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.

1 x 40 = 40    1 + 40 = 41
2 x 20 = 40    2 + 20 = 22
4 x 10 = 40    4 + 10 = 14
5 x   8 = 40    5 +   8 = 13

I also got the addends of 11 and solved each set to get the product
1 + 10 = 11    1 x 10 = 10
2 +   9 = 11    2 x   9 = 18
3 +   8 = 11    3 x   8 = 24
4 +   7 = 11    4 x   7 = 28
5 +   6 = 11    5 x   6 = 30
6 0
2 years ago
Is there more than one possible answer to part a
Maksim231197 [3]

There are apparently a huge number of correct answers ...
the statement of part-a that you've attached has so few
restrictions, requirements, or specifications.

4 0
3 years ago
If x=4x+5 what is the value of f(-3)
irina1246 [14]
You plug in -3 for x for 4(-3)+5 =-7
5 0
3 years ago
Read 2 more answers
How do find the general solution of sin7A=sinA+sin3A
const2013 [10]

Step-by-step answer:

Solve  

sin(7a) = sin(3a) + sin(a) ..................(1)

Let  

F(a)=sin(7a)-sin(3a)-sin(a)..................(2)

the equivalent problem to (1) is  

F(a)=0 ......................................(3)

F(a)

=sin(7a)-sin(3a)-sin(a)....apply trig sum identities

=sin(6a+a) - sin(3a) - sin(a)

=sin(6a)cos(a)+cos(6a)sin(a) -sin(3a) - sin(a)

apply double angle formulas

=(2sin(3a)cos(3a))cos(a) +

(cos^2(3a)-sin^2(3a))sin(a) -sin(3a) - sin(a)

simplify using sin^2(p)+cos^2(p) = 1

= (2sin(3a)cos(3a))cos(a) +

(1-2sin^2(3a))sin(a) - sin(3a) - sin(a)

simplify algebraically, note 1*sin(a) cancels sin(a)

= (2sin(3a)cos(3a))cos(a) -2sin^2(3a)sin(a) - sin(3a)

factor out sin(3a)

= sin(3a)(2cos(3a)cos(a)-2sin(3a)sin(a) - 1)

now use trig sum formula to reduce to cos(4a)

= sin(3a)(2cos(4a)-1)

So

F(a) = 0   if sin(3a) =0 ...................(4)

or

F(a) = 0   if cos(4a) = 1/2 ................(5)

using the zero product theorem

From (4)

sin(3a) = 0  

3a = sin-1(0) = n*pi

a = n*pi/3  ................................(6)

From (5)

cos(4a) = 1/2

4a = cos^-1(1/2) = 2n*pi +/- pi/3

a = (2n+1/3)pi/4 or (2n-1/3)pi/4............(7)

Combine (6) and (7) to give the general solution

a = n*pi/3 or (2n+1/3)pi/4 or (2n-1/3)pi/4 .....(8)

For checking, use your calculator to substitute every solution given in (8) into the function F(a) in equation (1) to confirm that the result is almost equality.  The small difference will be due to rounding errors of the calculators.  On mine, they work out to be of the order of +/- 10^-15.

6 0
3 years ago
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