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kow [346]
3 years ago
5

Suppose a certain religious university has a ratio of approximately 90 males to 125 females enrolled as a students. If he curren

t enrollment at the university is 15000 and every male on campus asks a female student to a dance, how many women will be without dates to the dance?
Mathematics
1 answer:
Nitella [24]3 years ago
7 0
How many males and how many females would there be if the total enrollment is 15000?

Ratio is 

  90 males      15000 - x
  ------------- = ---------------
   125 fem              x

Then 90x = 1875000 - 125x, or 215x = 1875000

                                                      x = approx 8720 females
                       and 15000-8720, or 6279 males

If every male finds a dance partner, that would leave (8720-6279) females, or 2440, without dance partners.  ;(

Check:  is the male:female ratio near 90:125?

Is 6279:8720 approx equal to 90:125?

Yes.  0.72 (approx) = 0.72 (approx).
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Answer:

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Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

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