To solve the set of equations given above, we can use the substitution method where we substitute one equation to the other and solving for one variable. We do as follows:
<span>0.4x - 0.1y = 2
x = 5 + 0.25y
0.2x + 0.5y = 1
</span>0.2(5 + 0.25y)+ 0.5y = 1
y = 0
x = 5
Therefore, the correct answer from the choices is option A, (5,0).
X = 11 x cos(22) = 10.199 = 10.2
To get the average, you must add all together and divide by the amount of numbers there are
(-4 - 6 - 3 - 1 + 0 + 2 - 1 - 3)/ 8
(-16)/8 = -2
-2 is your average
hope this helps
= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
The function that is linear is c
