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3 years ago

4230 estimated please ??????????????

Mathematics

2 answers:

Sladkaya [172]3 years ago

8 0

Answer:4200

Step-by-step explanation:

lianna [129]3 years ago

5 0

Answer would be 4200

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100.53 rounded to nearest tenth

Alja [10]

Answer:

100.5

Step-by-step explanation:

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3 years ago

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Divide 112 in the ratio 3 : 4

Tanya [424]

48:64
3+4 = 7
112/7 = 16
16 * 3 = 48
16 * 4 = 64

5 0

3 years ago

SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).

Ann [662]

Answer:

Required series is:

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

Step-by-step explanation:

Given that

$f'(x) = -\frac{1}{1 + x^{2}}$ ---(1)

We know that:

$\frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}}$ ---(2)

Comparing (1) and (2)

$f'(x)=-(tan^{-1}x)$ ---- (3)

Using power series expansion for $tan^{-1}x$

$f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx$

$= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]$

$=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}$

$=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

$tan^{-1}(0)=0 \implies C=0$

Hence,

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

7 0

4 years ago

What is the domain of the function

Svet_ta [14]

Answer:

The answer would be D, 0 < x < 4

Step-by-step explanation:

Because Domian is left to right of a function, so left to right would be 0 to 4

7 0

3 years ago

Find the solution to: -2x+7<-41

Karolina [17]

Answer:

x>24

Step-by-step explanation:

Solve like a normal equation :)

-2x<-48

Now we divide.

-x<-24

Note: Whenever dividing by a negative, you have to flip the sign of the inequality!

x>24

7 0

3 years ago

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