3 years ago

How to use the proper formula

2 answers:

4 0

Just plugin -3 where the x is in $2x^2 - x$
$f(-3) = 2x^2 - x$
$f(-3) = 2(-3)^2 - (-3)$
$f(-3) = 2(9) - (-3)$
$f(-3)= 18 - (-3)$
$f(-3) = 21$
$21$ <------The answer

Elis [28]3 years ago

3 0

21 is the answer
thanks (:

You might be interested in

I NEED HELP XDDD what is 36 = 4x = ?

Mice21 [21]

Answer:

x = 9

Step-by-step explanation:

divide both sides of the equation by 4 to isolate the x variable according to algerba. Hope it helps!

6 0

2 years ago

Read 2 more answers

Solve equation by using the quadratic formula.

adoni [48]

ANSWER IS C because I looked it up

3 0

3 years ago

Need help with question 7 and 8 with awnser please check photo for problems

Tanzania [10]

Answer:

7) 230mm

8) 98m

Step-by-step explanation:

7x+8+6x+6+9x-4 =22x+10

if x is 10 mm, 22(10)+10 =230mm

8) perimeter of rec =2( l + w )

=2 ( 2x-5+2x+6 ) = 8x + 2

if x is 12 metres, 8(12)+2 =98m

7 0

3 years ago

Answer The Questions

lana66690 [7]

Answer:

Step-by-step explanation:

That’s easy

5 0

3 years ago

Read 2 more answers

Rewrite the expression with a rational exponent as a radical expression.

Vilka [71]

Answer:

$\sqrt{5}$

Step-by-step explanation:

we know that

The "power rule" tells us that to raise a power to a power, just multiply the exponents

$(a^{m})^{n}=a^{m*n}$

we have

$(5^{\frac{3}{4}})^{\frac{2}{3}}$

Applying the "power rule"

$(5^{\frac{3}{4}})^{\frac{2}{3}}=5^{\frac{3}{4}*\frac{2}{3}}=5^{\frac{1}{2}}=\sqrt{5}$

5 0

3 years ago