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elena-s [515]
3 years ago
13

Find the slope of the line through the given points

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0
I can’t solve all of them but maybe one and I will give you the formula for you to solve the rest.
Slope = (y2 -y1) / (x2 -x1).
m= ( 16 -(-3)) / ( -14 -(-9))
m = (16+3)/(-14+9)
m = 19/ -5
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F(x) = x5 + 5x4 - 5x3 - 25x2 + 4x + 20
Pie

Answer:

-4(5-x)

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent to 5!<br> 5^4*3^2<br> 5-4-3-2-1<br> 5.4.3-2.1<br> 5+4+3+2+1<br> 5.1
baherus [9]
The first one is like 5x5x5x5 which is 625 multiplied by 3x3 which is 9 and together the product will be 5,625.

The second one is 5-4 which is 1-3 which is -2 - 2 = -4 - 1 which is -5 so it’s not it because it’s the opposite of the number we need to find.

The third one is kind of messed up because there’s no such thing as 5.4.3 so sorry I can’t do that one.

The fourth one is 15 because you basically add the numbers up.

And the fifth is not 5. It’s 5.1 so that’s not it either.

So I’m sorry I can’t find the answer but at least I have you some background :/

6 0
3 years ago
What is 5.138 + 2.624 = ? (show ur work)
Mrac [35]

Answer:

7.762

Step-by-step explanation:

Brainliest!

3 0
2 years ago
Simplify 4x^2 / 3 X 6/ 8x
Leokris [45]

Answer:

x

Step-by-step explanation:

The answer to

\frac{4 {x}^{2} }{3}  \times  \frac{6}{8x}

= x

3 0
3 years ago
Read 2 more answers
In the context of relationship between variables, increases in the values of one variable are accompanied by increases in the va
garik1379 [7]

Answer:

A. Positive linear.

Step-by-step explanation:

We have that both variables increases, then we have a positive relation. A curvilinear option can not be possible because with this option in some regions could happen that when one variable increases the other one decreases. The negative linear relation can no be because with this option when one variable increases the other decreases. A non linear option is the same as a curvilinear option then can not be possible. Then the best option is a positive linear relationship.

7 0
3 years ago
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