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Pachacha [2.7K]
4 years ago
7

How do you determine which tool to use for lab activities?

Chemistry
1 answer:
Gnesinka [82]4 years ago
4 0

Answer:

It all depends what your working with and what experiment your planning on doing .

Explanation:

Say if you were working with chemicals you would the tools that would help you protect your body like gloves,googles, apron , etc

So in conclusion it depends what your doing to know what tools you are going to need

You might be interested in
If 10.0g of powdered iron is heated with 10.0g of sulfur in an open crucible, what is the mass of iron (II) sulfide that is form
Ugo [173]

Answer:

See Explanation

Explanation:

                     8Fe        +        S₈                =>        8FeS

Given:            10g                  10g

moles      10g/56g/mol     10g/256g/mol

                = 0.179mol Fe   = 0.039mol S₈

Reduce => divide mole values by respective coefficients; smaller value is Limiting Reactant.

                 0.179/8 = 0.022      0.039/1 = 0.039  

       => Fe is limiting reactant

                       8Fe        +               S₈                   =>         8FeS    

Given:     10g/56g/mol          10g/256g/mol

               = 0.179mol              = 0.039 mol                  0.179mol FeS produced

                                          1/8(0.179)mol S₈ used        (coefficients are equal,

                                          = 0.022 mol S₈ used       => moles Fe = moles FeS)

                                         = (0.039 - 0.022)mol S₈     = 0.179mol FeS

                                         remains in excess              =(0.179mol)(88g/mol)

                                         = 0.0166 mol S₈ (excess)  = 15.8 g FeS  

                                         = (0.0166mol)(256g/mol)           (Theoretical Yield)

                                         = 4.26g S₈ in excess

7 0
3 years ago
From the list of substances, identify each as a strong acid, strong base, or neither a strong acid nor a strong base.
Dafna11 [192]

Answer:

HNO3 is a strong acid

HCl is also a strong acid

NaCl is a salt so it is neither a strong acid nor a strong base

Ca(OH)3 is a strong base

Explanation:

8 0
3 years ago
PLS HURRY: 217 mL of Helium gas at 551oC is brought to standard temperature (0oC) while the pressure is held constant. What is t
krok68 [10]
71.9 mL is the answer
6 0
3 years ago
Three different sub-atomic particles are described below: Particle X: Uncharged Particle Y: Carries positive charge Particle Z:
bazaltina [42]

 The statement  which is true  about  the three sub atomic particles  is

X is  a neutron,Y is a protons and z is an electron

<u><em>Explanation</em></u>

  •  Atom  has three  sub  atomic    particles,that  is  neutrons,protons and electrons.
  • Neutrons have no electric  charge,protons  are positively  charged while electrons  are  negatively  charged.
  • Both  neutrons and proton are located in the nucleus while electrons  are  located outside the  nucleus.
  • since electrons   are located  outside the  nucleus  they  orbit  around the nucleus.
3 0
3 years ago
Read 2 more answers
can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g
V125BC [204]

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) <u>1278.50</u> = 6 sig figs

2) <u>12</u>0000 = 2 sig figs

3) <u>90027.00</u> = 7 sig figs

4) 0.00<u>53567</u> = 5 sig figs

5) <u>67</u>0 = 2 sig figs

6) 0.00<u>730</u> = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

4 0
2 years ago
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