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Travka [436]
2 years ago
7

can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g

ood.

Chemistry
1 answer:
V125BC [204]2 years ago
4 0

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) <u>1278.50</u> = 6 sig figs

2) <u>12</u>0000 = 2 sig figs

3) <u>90027.00</u> = 7 sig figs

4) 0.00<u>53567</u> = 5 sig figs

5) <u>67</u>0 = 2 sig figs

6) 0.00<u>730</u> = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

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What coefficient should be used to make the following equation balanced? N2+O2--&gt; _NO
IgorLugansk [536]
<h2>                  ║∧║······→Hello.←······║∧║</h2>

                                          Your answer should be:

                                                N2 + O2 → 2NO

<h2>····················································································</h2>

I hope this answered your question!

Thanks for spending time reading this :)

(<em>A brainliest would be appreciated!)</em>

⊕If this answer doesn't answer your question or you are displeased by it please tell me in the comments I would like to know. And if I can, I will remove it.⊕

<h2>Have a wonderful day</h2>
7 0
3 years ago
I need help
Liono4ka [1.6K]

Answer:

d and e - Sodium and antimony

Explanation:

The atomic numbers remain the same, while the mass numbers change (because neutrons are being added or taken away).

sodium has an atomic number of 19 and a mass number of 39 - in d, it has an atomic number of 19 but a mass number of 40. therefore, it is an isotope

antimony has an atomic number of 51 and a mass number of 121.60 - in e, it has an atomic number of 51, but a mass number of 123. therefore, it is an isotope

6 0
3 years ago
How many grams of barium chloride (BaCl2) are there in 0.187 mol?<br> 0.187 mol
igor_vitrenko [27]

Answer:

38.9 grams of BaCl_2

Explanation:

0.187 mol BaCl2 x \frac{208 g}{1 mol}

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2

8 0
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In a sample of oxygen gas at room temperature, the average kinetic energy of all the balls stays constant. Which postulate of ki
Levart [38]

Answer:

Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.

Explanation:

When a gas is paced in a container, the molecules of the gas have little or no intermolecular interaction between them. There is a lot of space between the molecules of the gas.

The gas molecules move at very high speed and collide with each other and with the walls of container.

The collision of these particles with each other is perfectly elastic hence the kinetic energy of the colliding gas particles do not change.

7 0
3 years ago
How many moles of butane (C4H10) must be burned in an excess of O2 to produce
Sedbober [7]

Answer: 6,25 moles

Explanation: mark amount of butane x.

From equation you can calculate x in a following way:

2/x = 8/25. 8x = 50. And x = 6,25

4 0
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