Question

To titrate 50.00 milliliters of an unknown HC2H3O2 sample, use 43.00 milliliters of a standard 0.1000 M NaOH titrant. What is the molarity of the HC2H3O2? 0.1000 M 0.08600 M 0.1163 M 2150 M

Answer 1

The molarity of the acid is 0.086 00 mol/L.

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

Since 1 mol of acid reacts with 1 mol of base, we can use the formula

M₁V₁ = M₂V₂

M₁ = ?; V₁ = 50.00 mL
M₂ = 0.1000 mol/L; V₂ = 43.00 mL

M₁ = M₂ × $\frac{ V_{2}}{ V_{1}}$ = 0.1000 mol/L × $\frac{43.00 mL}{50.00 mL}$ = 0.086 00 mol/L