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Vlad1618 [11]
2 years ago
14

What is the mass of silver chloride.required to plate 295mg.of pure.silver

Chemistry
1 answer:
vekshin12 years ago
3 0


17 hope its correct pls rate 5 star


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Calculate the pH of a solution prepared by dissolving 0.150 mol of benzoic acid and 0.300 mol of sodium benzoate in water suffic
jok3333 [9.3K]

Answer : The pH of a solution is, 4.50

Explanation : Given,

K_a=6.30\times 10^{-5}

Concentration of benzoic acid (Acid) = 0.150 M

Concentration of sodium benzoate (salt) = 0.300 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.30\times 10^{-5})

pK_a=5-\log (6.30)

pK_a=4.20

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=4.20+\log (\frac{0.300}{0.150})

pH=4.50

Thus, the pH of a solution is, 4.50

8 0
3 years ago
Feeling the heat when touching a hot piece of metal is an example of
Tom [10]

Answer:

Conduction

Explanation:

Conduction is between one solid and another solid

3 0
2 years ago
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Which procedure is an attempt to correct a genetic disorder by replacing a mutated gene with a normal allele?
-Dominant- [34]
Artificial selection
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2 years ago
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a 15.0 L tank of gas is contained at a high pressure of 8.20*10^4. The tank is opened and the gas expands into an empty chamber
Nostrana [21]

Answer:

P_2=20.5

Explanation:

Assuming that temperature is constant

According to Boyle's Law, at constant temperature pressure is inversly proportional to the volume  and mathematically it can be expressed as:

P_1V_1 = P_2V_2..........1

P_1=8.2 \times 10^4

P_2=?

V_1=15L

V_2=6.00 \times 10^4L

from the first equation after putting all the value

we get,

P_2=20.5

8 0
3 years ago
Solution A is yellow when alizarin yellow is added and blue when thymol
olga2289 [7]

Answer:

D. 6.3 x 10-5 mol/L NaOH

Explanation:

Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9

That means the pH of the solution is between 9 - 10.1

Any acid as HCl could have a pH of these.

The solution of 3.2x10⁻⁴M NaOH has a pH of:

pOH = -log[OH-] = 3.49

pH = 14-pOH = 10.51. The pH of the solution is not 10.5

Now, the solution of 6.3x10⁻⁵M NaOH has a pH:

pOH = -log[OH-] = 4.2

pH = 14-pOH = 9.8

The pH of the solution could be 9.8. Right option is:

<h3>D. 6.3 x 10-5 mol/L NaOH</h3>
4 0
3 years ago
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