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Vladimir [108]
3 years ago
5

Convert to standard circle form

d="TexFormula1" title=" x^{2} +y ^{2} -6x-4y-12=0 " alt=" x^{2} +y ^{2} -6x-4y-12=0 " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25
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