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4 years ago

5

Convert to standard circle form

d="TexFormula1" title=" x^{2} +y ^{2} -6x-4y-12=0 " alt=" x^{2} +y ^{2} -6x-4y-12=0 " align="absmiddle" class="latex-formula">

1 answer:

DIA [1.3K]4 years ago

7 0

x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25

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Marysya12 [62]

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3 years ago

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Step-by-step explanation:

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3 years ago

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ExtremeBDS [4]

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