Answer: It's 11683.9
Step-by-step explanation:
You can subtract 9 from the 713 value and trace until you get a multiple of 7 or vice versa.
It could be one of :
80 figilbuttons and 7 rybirens
or
14 rybirens and 73 figilbuttons
2)The goal is to isolate the variable and get is down to x<?. This is actually a two step inequality problem. 0.7x - 2 < 5.5 +2 +2 0.7x<7.5 This implies: x<10.714 The way to graph this is to place an open circle of the number 10.714 on the number line indicating this number is not included as a solution to the inequality. Then draw the arrow going left from the open circle indicating all numbers from -∞ to 10.714.
1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
To know more about quartile visit:
brainly.com/question/8737601
#SPJ4
I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
Answer:
y=4
Step-by-step explanation:
its asking which one you can answer without any more context, in this case its y=4 because all the other ones evolving x lead to a rabbit hole and will take you in circles.
