Ask question

Ask question

All categories

3 years ago

5

The horseshoe crab looks very similar to its fossil ancestor from the Jurassic era. Why has the horseshoe crab not evolved?

2 answers:

kolezko [41]3 years ago

8 0

The answer is A. Natural selection always favors individuals in a population that are well adapted to their environment. These individuals are able to get to maturity and pass down their genes to subsequent generations. Any disadvantages mutations in the population are eliminated by natural selection.

aniked [119]3 years ago

7 0

Answer:

its a

A. Its original form always remained well adapted to its environment.

because it takes time to adapt to a new place

You might be interested in

The acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on Earth’s surface. Th

Lorico [155]

1/3 the weight than it is on earth, duh

3 0

3 years ago

Read 2 more answers

An electron is released from rest in a weak electric field given by vector E = -1.30 10-10 N/C Äµ. After the electron has travel

Murljashka [212]

Answer:

v = 6.45 10⁻³ m / s

Explanation:

Electric force is

F = q E

Where q is the charge and E is the electric field

Let's use Newton's second law to find acceleration

F- W = m a

a = F / m - g

a = q / m E g

Let's calculate

a = -1.6 10⁻¹⁹ / 9.1 10⁻³¹ (-1.30 10⁻¹⁰) - 9.8

a = 0.228 10² -9.8

a= 13.0 m / s²

Now we can use kinematics, knowing that the resting parts electrons

v² = v₀² + 2 a y

v =√ (0 + 2 13.0 1.6 10⁻⁶)

v = 6.45 10⁻³ m / s

4 0

3 years ago

The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371

arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

$q=m\times c\times (T_2-T_1)$

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = $4.18J/g.K$

$T_1$ = initial temperature of water = 293.0 K

$T_2$ = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

$q=250g\times 4.18J/g.K\times (371.2-293.0)K$

$q=81719J$

Now we have to calculate the enthalpy of combustion of octane.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

$\Delta H=\frac{-81719J}{0.015mole}$

$\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol$

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0

4 years ago

At a particular temperature, the speed of sound is 330 m/s and its frequency is 990 Hz. Choose the correct wavelength of this so

koban [17]

Answer:

1/3 M

I hope this helps :) sorry its late

8 0

3 years ago

Read 2 more answers

The vertical columns in the periodic table are called _____________. families periods rows

bonufazy [111]

Answer:

families

Explanation:

periods are horizontal

4 0

3 years ago

Read 2 more answers