Answer:
W = -1844.513 J
Explanation:
GIVEN DATA:
mass of spider man is m 74 kg
vertical displacement if spider is 11 m
final displacement = 11 cos 60.6 = - 6.753 m
change in displacement is = -6.753 - (-11) = 4.25 m
gravity force act on spiderman is f = mg = 74 × 9.8 = 725.2 N
work done by gravity is 

where 180 is the angle between spiderman weight and displacement
W = -1844.513 J
It will increase..........................
Both options 5 and 6
Explanation:
Let us consider option 5,
In option 5 body is moving up with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.
Let us consider option 6,
In option 6 body is moving down with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.
Determine the frequency and the speed of these waves. The wavelength is 8.6 meters and the period is 6.2 seconds. Now find speed using the v = f. λ equation<span>.</span>
Answer:
The cylinder’s total kinetic energy is 1.918 J.
Explanation:
Given that,
Mass = 4.1 kg
Radius = 0.057 m
Speed = 0.79 m/s
We need to calculate the linear kinetic energy
Using formula of linear kinetic energy



We need to calculate the rotational kinetic energy




The total kinetic energy is given by



Hence, The cylinder’s total kinetic energy is 1.918 J.