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Vera_Pavlovna [14]
4 years ago
12

Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto

r is always changing. B. The velocity of the planet is constant. C. The speed of the planet is always changing. D. The acceleration vector of the planet points directly away from the star.
Physics
2 answers:
Sunny_sXe [5.5K]4 years ago
6 0

Answer;

A.The direction of the velocity vector is always changing.

Explanation;

-A circular orbit of a planet around a star is an example of uniform circular motion (its speed remains constant).

--When a planet has just the right speed (for a given radius of orbit), then it will travel in circular motion with a constant speed. This is called uniform circular motion. Note that the velocity vector changes direction although the speed is constant. This means that there must be a net force on the planet.

Luda [366]4 years ago
4 0
<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well. That implies option A is correct.</span>
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Two instruments produce a beat frequency of 5 Hz. If one has a frequency of 264 Hz, what could be the frequency of the other ins
Lerok [7]

Answer:

259 Hz or 269 Hz

Explanation:

Beat: This is the phenomenon obtained when two notes of nearly equal frequency are sounded together. The S.I unit of beat is Hertz (Hz).

From the question,

Beat = f₂-f₁................ Equation 1

Note: The frequency of the other instrument is either f₁ or f₂.

If the unknown instrument's frequency is f₁,

Then,

f₁ = f₂-beat............ equation 2

Given: f₂ = 264 Hz, Beat = 5 Hz

Substitute into equation 2

f₁ = 264-5

f₁ = 259 Hz.

But if the unknown frequency is f₂,

Then,

f₂ = f₁+Beat................. Equation 3

f₂ = 264+5

f₂ = 269 Hz.

Hence the beat could be 259 Hz or 269 Hz

8 0
3 years ago
An object is 30.0 cm to the left of a convex lens with a focal length of +8.0 cm. Draw a ray diagram of the setup showing the lo
Ostrovityanka [42]
The distance should be 11 cm and the image will be inverted (and smaller)
I used the Lens Equation:
\frac{1}{obj.}+ \frac{1}{im.}  = \frac{1}{f}
Where:
obj. is the distance of the object
im. is the distance of the image
f is the focal length

4 0
4 years ago
Please help me in science plss​ <br><br><br>I give brainliest to Answer this plss
Elenna [48]
Stan looga
this is correct answer
8 0
3 years ago
Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h
katrin2010 [14]

Answer:

a) 7.5425 * 10^-7 C

b) 3.7712 * 10^-7 C ; 1.5085 * 10^-6 C

Explanation:

Part a)

F_{elect} = \frac{k*q_{1}*q_{2} }{R^2} \\q_{1} = q_{2} = q\\q = \sqrt{\frac{F_{elect} * R^2}{k} }\\ = \sqrt{\frac{0.2 * 0.16^2}{9*10^9} }\\\\ q = 7.5425 * 10 ^(-7) C

Part b)

F_{elect} = \frac{k*q_{1}*q_{2} }{R^2} \\q_{1} = 4*q_{2} \\q = \sqrt{\frac{F_{elect} * R^2}{k*4} }\\ = \sqrt{\frac{0.2 * 0.16^2}{4*9*10^9} }\\\\ q_{2}  = 3.7712 * 10 ^(-7) C\\\\q_{1}  = 1.5085 * 10 ^(-6) C

3 0
3 years ago
Why we have leap year?
Marina CMI [18]

Answer:February 29 is a date that usually occurs every four years, and is called leap day. This day is added to the calendar in leap years as a corrective measure, because the Earth does not orbit the sun in precisely 365 days.

Explanation: brainlest plz

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3 years ago
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