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3 years ago

13

If Planet Y orbits the Sun but does not rotate on its axis at all, how long would a day be on Planet Y?

1 answer:

scoundrel [369]3 years ago

4 0

A day which in this case is longer than a year

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A laser pulse with wavelength 532 nm contains 3.85 mj of energy. how many photons are in the laser pulse?

erastovalidia [21]

Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>

Explanation:

1) Data:

E = 3.85mJj (mili joules) = 3.85×10⁻³ J

λ = 532 nm = 532 × 10⁻⁹ m

number of photons ?

2) Physical principles

a) The energy of a photon is given by the equation E = hν.

Where:

h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
ν is the freguency of the light

b) The wavelength, λ, and the frequency, are related by the equation:

ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s

3) Solution:

ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz

E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J

Divide the total energy by the energy of one photon to find the number of photons:

3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer

4 0

3 years ago

Read 2 more answers

How old do you think I am by my profile picture

Ulleksa [173]

Answer:

12

Explanation:

trust me bro just trust

5 0

3 years ago

Read 2 more answers

An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.

jekas [21]

Answer:

$\varphi_1= 796.25 N m^2/C$

$\varphi_2= 0 N m^2/C$

$\varphi_3=686.1 N m^2/C$

Explanation:

From the question we are told that

Electric field of intensity $E= 3.25 kN/C$

Rectangle parameter Width $W=0.350 m$ Length $L=0.700 m$

Angle to the normal $\angle=30.5 \textdegree$

Generally the equation for Electric flux at parallel to the yz plane $\varphi_1$ is mathematically given by

$\varphi_1=EA cos theta$

$\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0$

$\varphi_1= 796.25 N m^2/C$

Generally the equation for Electric flux at parallel to xy plane $\varphi_2$ is mathematically given by

$\varphi_2=EA cos theta$

$\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90$

$\varphi_2= 0 N m^2/C$

Generally the equation for Electric flux at angle 30 to x plane $\varphi_3$ is mathematically given by

$\varphi_3=EA cos theta$

$\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5$

$\varphi_3=686.072219 N m^2/C$

$\varphi_3=686.1 N m^2/C$

7 0

3 years ago

A blue car with mass mc = 427 kg is moving east with a speed of vc = 20 m/s and collides with a purple truck with mass mt = 1282

polet [3.4K]

Answer:8540 kg-g/s

Explanation:

Given

mass of blue car $m_c=427 kg$

velocity of blue car $v_c=20 m/s$

mass of the truck $m_t=1282 kg$

speed of truck $v_t=13 m/s$

After collision they stick and lock together

Let v be the velocity of combined system at angle \theta from vertical

Conserving momentum in east direction

$m_c\times v_c=(m_c+m_t)v\cos \theta$

$427\times 20 =1709\times v\cos \theta$ ------1

Conserving Momentum in Y direction

$m_t\times v_t=(m_c+m_t)v\sin \theta$

$1282\times 13 =1709\times v\sin \theta$ -------2

squaring and then adding 1 & 2 we get

$(8540)^2+(16666)^2=(1709)^2\cdot v^2$

v=10.95 m/s

initial momentum of car $=427\times 20=8540 kg-m/s$

6 0

4 years ago

What is the cause of the beats

mestny [16]

When two sound waves of different frequencies approach the ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - producing beats

3 0

3 years ago