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Kamila [148]
3 years ago
13

If Planet Y orbits the Sun but does not rotate on its axis at all, how long would a day be on Planet Y?

Physics
1 answer:
scoundrel [369]3 years ago
4 0

A day which in this case is longer than a year

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Question is in the picture!
raketka [301]
Any change in velocity is called an acceleration. The rock is experiencing the gravitational force from the earth, accelerating it towards the ground.
8 0
4 years ago
Perform the following mathematical operation and report answer to the correct number of significant figures 143.6 divided by 21.
Svetllana [295]

The answer to the correct number of significant figures is 6.774.

<h3>What is quotient?</h3>

When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.

Divide 143.6 ÷ 21.2

143.6/21.2 = 1436/212

                  =6.77358

The quotient is rounded to three significant figures after decimal

143.6 ÷ 21.2 = 6.774

Thus, the answer to the correct number of significant figures is 6.774

Learn more about quotient

brainly.com/question/27796160

#SPJ1

7 0
2 years ago
At its limit the history of science touches on
myrzilka [38]

Answer:

Explanation:

the development of the history of science, the histories of the individual scientific disciplines have played an enormously significant role. The goals and functions of these have recently received considerable attention, both because of the influence that such histories have had on the legitimacy and self-image of the disciplines and also because of the adaptability that they have shown when faced with the conceptual and methodological changes that they have undergone.

3 0
3 years ago
A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se
igomit [66]

Answer:

W_2=-12J

Explanation:

The work of force 2 will be given by the vectorial equation W_2=F_2.d. We know the value of F_1 and have information about its movement, which relates to the net force F=F_1+F_2.

About this movement we can obtain the acceleration using the equation v_f^2=v_i^2+2ad. Since it departs from rest we have a=\frac{v_f^2}{2d}.

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1

And we had the work done by force 2 as:

W_2=F_2.d=\frac{mv_f^2}{2}-F_1d

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>

<em>W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}</em>

<em>Which leads us to the previous equation straightforwardly.</em>

6 0
3 years ago
Can earthquakes with a magnitude between 3.0 and 6.0 produce high intensity levels?
laiz [17]
3.0 typically is only felt by people who are resting or on the up stairs of buildings. 6.0 is more intense. I would say a 6.0 can produce high intensity levels. A 6.0 can damage buildings of good design and structure. Damagable in poorly built or badly designed structures. Some chimneys may be broken.
5 0
3 years ago
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