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juin [17]
3 years ago
12

What is the value of r in this equation? 4(x-3)-r+2x=5(3x-7)-9x

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

4(x-3)-2+2x=5(3x-7)-9x

4x-12-r+2x=5(3x-7)-9

4x-12-r+2x=15x-35-9x

6x-12-r=15x-35-9x

6x-12-r=6x-35

add 12 to -35 which equals -23.

add 6x+6x it cancels out to 0.

-r=-23

to make r positive just add it -23

since 23 is already negative it would become a positive because a negative + negative= positive

answer: r=23


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Step-by-step explanation:

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Answer:  \frac{2x(5x + 1)}{4x - 1}

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\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2} ÷ \frac{2x^{2}-6x}{5x^{2}+11x + 2}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} ÷ \frac{2x(x - 3)}{(5x + 1)(x + 2)}

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The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
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