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Vlad [161]
4 years ago
9

Rachel is helping her younger brother replace a broken part in his toy ambulance this part is responsible for converting electri

c energy into light energy which of these devices should I use for the replacement
Physics
1 answer:
MrRissso [65]4 years ago
8 0
Headlights and other lights
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Calculate the force it would take to accelerate a 250 kg motorcycle at a rate of 5m/s^2
bija089 [108]

1250 N of force is required to accelerate a 250 kg motorcycle at a rate of 5 m/s^{2}.

<u>Explanation:</u>

As per the second law of motion stated by Newton, the net unbalanced external force acting on any object is directly proportional to the product of mass and acceleration experienced by the object.

As here the object is given as motorcycle of mass 250 kg. Also the acceleration exhibited by the motorcycle is stated as 5 m/s^{2}. So from the Newton's second law of motion,

Net force = Mass of the motorcycle× Acceleration of the motorcycle

Net force = 250 × 5 = 1250 N.

Thus, 1250 N of force is required to accelerate a 250 kg motorcycle at a rate of 5 m/s^{2}.

5 0
3 years ago
Two measurments that are the same as each other are called_____?<br><br><br> What are they called???
Softa [21]

Precision refers to the closeness of two or more measurements to each other. Using the example above, if you weigh a given substance five times, and get 3.2 kg each time, then your measurement is very precise. Precision is independent of accuracy.

8 0
3 years ago
You wish to buy a motor that will be used to lift a 10-kg bundle of shingles from the ground to the roof of a house. The shingle
gogolik [260]

Answer:

\tau=19.21\ N-m

Explanation:

It is given that,

Mass of bundle of shingles, m = 10 kg

Upward acceleration of the shingles, a=1.5\ m/s^2

The radius of the motor of the pulley, r = 0.17 m

Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :

T-mg=ma

T=m(g+a)

T=10\times (9.8+1.5)

T = 113 N

Let \tau is the minimum torque that the motor must be able to provide. It is given by :

\tau=r\times T

\tau=0.17\times 113

\tau=19.21\ N-m

So, the minimum value of torque is 19.21 N-m. Hence, this is the required solution.

4 0
3 years ago
A bullet of .05 kg is fired into a block of wood. Knowing that the bullet left the gun with a muzzle velocity of 350. m/s, and t
Lunna [17]

We know, Impulse of a body is change in momentum.

Also, the final velocity of wood block is 0 m/s.

So, Impulse = Final Momentum - Initial Momentum

Impulse = 0 - ( 0.05 kg × 350 m/s )

Impulse = - 17.5 kg m/s

Therefore, the impulse exerted by the wood on the bullet is -17.5 kg m/s .

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=See%20%5C%3A%20%20Attachment.%20%20%5C%3A%20" id="TexFormula1" title="See \: Attachment. \:
Tcecarenko [31]
So acceleration = (final velocity - initial velocity)/time

So (fv-iv)/t=a

(45-110)/4.5

Gives you (-130/9)km/h^2

You may have to convert the SI units so just follow my steps and change what must be changed
4 0
3 years ago
Read 2 more answers
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