Answer:
Explanation:
The surface charge density on the inside surface of the sphere is -150nC/m2
Charge on the inner surface = - 4 π x (.05)² x 150 x 10⁻⁹
= - 4.71 x 10⁻⁹ C
This is the bound charge . This charge will be bound by charge at the centre
equal to the same charge but of opposite nature .
So charge at the centre
Q = + 4.71 x 10⁻⁹ C
B) Imagine a Gaussian surface with radius equal to 4 cm
If E be electric field on the surface
Flux through the surface
4 π x (.04)² x E = Q / ε₀
= 4.71 x10⁻⁹ / 8.85 x 10⁻¹²
= .532 x 10³
E = .532 x 10³ / 4 π x (.04)²
= 26473 N/C
C )Imagine a Gaussian surface with radius equal to 8 cm
If E be electric field on the surface
Flux through the surface
4 π x (.08)² x E = Q / ε₀
= 0 / 8.85 x 10⁻¹² ( Total charge inside will be -Q + Q = 0 )
= 0
D)
Total charge on the outer surface
= 4 π x (.12)² x 150 x 10⁻⁹
= 27.13 x 10⁻⁹ C
Imagine a Gaussian surface with radius equal to 20 cm
If E be electric field on the surface
Flux through the surface
4 π x (.12)² x E = Q / ε₀
= 27.13 x10⁻⁹ / 8.85 x 10⁻¹² ( - Q + Q will cancel each other )
= 3.065 x 10³
E = 3.065 x 10³ / 4 π x (.12)²
= 16946.43 N/C
