Ask question

Ask question

All categories

Alenkasestr [34]

3 years ago

12

Wendell is making punch for a party does The recipe he is using says to mix for cups pineapple juice, 8 cups orange juice, and 1

2 cups lemon lime soda and order to make 18 servings of punch how many cups of punch does the recipe make

1 answer:

dalvyx [7]3 years ago

4 0

Answer:

I believe 42.

Step-by-step explanation:

You might be interested in

Solve each quadratic equation by factoring with grouping. 5v2 – 18v = -9

djyliett [7]

Answer:

v = 3 , 3/5

Step-by-step explanation:

$5 {v}^{2} - 18v + 9 = 0 \\ 5 {v}^{2} - 3v - 15v + 9 = 0 \\ v(5v - 3) - 3(5v - 3) = 0 \\ (5v - 3)(v - 3) = 0 \\ v = 3 \\ v = \frac{3}{5}$

6 0

3 years ago

This table shows the number of girls enrolled in school by class. If a student is chosen at random from this group, which is the

Naya [18.7K]

Answer:

102/526

Step-by-step explanation:

This would be the answer because when u add the amount of freshman plus sophomore plus juinior and plus senior, you get the result of 526. so that would be the denominator while the number of seniors would be the numerator...

6 0

3 years ago

-8(2b-7)-9(b-5)<br>simplify

GenaCL600 [577]

Answer:

<h2>-25b + 101</h2>

Step-by-step explanation:

$-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101$

3 0

3 years ago

Read 2 more answers

This is a question on my partial fractions homework, but no matter what I try I can't figure it out..

Ierofanga [76]

$\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}$
$\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}$
$\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)$
$\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3$

So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
$=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$

where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
$=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)$
$=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2$
$=\dfrac23+\ln\dfrac89$

4 0

3 years ago

yawa3891 [41]

Answer:

C. 4.6

Step-by-step explanation:

If you subtract 3.0 from 1.4 you get 1.6, which is the can be added to 3.0 to find the missing value.

8 0

3 years ago