There exist an abbreviation that ALL - S - T - C where all trigonometric functions in first quandrant are positive. S, T, and C are the first letters of the trigonometric functions that are positive in quadrant 2, 3, and 4, respectively. This also means that in the same quadrant, their reciprocals are also positive. For the given above, it is in Quadrant 3 where T is positive and cosine is negative.
I assume you mean: Order the following from least to greatest:
17/9, 15 divided by 6, 30, and 3^3
17/9 = 1 8/9
15/6 = 2 1/2
3^3 = 9
So it would be: 17/9, 15 divided by 6, 3^3, and 30
Make necessary adjustments if it was actually 6/30; the wording was confusing.
Answer:
Hay un máximo de tres ceros en el producto de un número distinto de cero cero menor que 10 y 500
Para poder ver esto, la forma más fácil para resolver este problema es multiplicar todos los números entre 1 y 9 por 500, es decir:
01*500 = 500
2*500 = 1.000
3*500 = 1.500
4*500 = 2.000
5*500 = 2.500
6*500 = 3.000
7*500 = 3.500
8*500 = 4.000
9*500 = 4.500
Como vemos, si multiplicamos a 500 por cualquier número par, entonces obtenemos un número con tres ceros, mientras que si este es impar solamente obtenemos dos ceros
dame coronaa
Numerical expressions contain numbers, while algebraic expressions contain variables and numbers.
<u>Numerical Expression</u>
"Difference" indicates that we'll be subtracting 13 from 48.
48 - 13 = 35
<u>Algebraic Expression</u>
Variables represent the unknown number, in this case the difference between 48 and 13. Let d represent the difference between the two.
48 - 13 = d
35 = d
To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
