Acceleration = (change in speed) / (time for the change)
change in speed = (speed at the end) - (speed at the beginning)
Our cyclist's change in speed = (3 m/s) - (8 m/s) = -5 m/s
Acceleration = (-5 m/s) / (60 seconds)
<em>Acceleration = -1/12 m/s²</em>
The distance of tiger's leap from the base of rock is 5.58 m
It is a question of two dimensional motion
The time of motion in two dimensional motion is given by:
t= 
where y is the height and g is the acceleration due to gravity
y is given to be 7.5m and let us assume g to be 9.8 m/s^2
t = 
= 1.24s
Using time and speed,
We know that distance is the product of speed and time,
Distance= speed x time
speed is given to be 4.5 m/s
distance from the base of rock = 4.5 x 1.24
= 5.58m
Hence the distance of tiger's leap from the base of rock is 5.58 m
Disclaimer:
The acceleration due to gravity is assumed to be 9.8 m/s^2
For further reference:
brainly.com/question/11213880?referrer=searchResults
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The average current density in the wire is given by:

where I is the current intensity and A is the cross-sectional area of the wire.
The cross-sectional area of the wire is given by:

where r is the radius of the wire. In this problem,
, so the cross-sectional area is

and the average current density is

Answer:
A= 203 KJ
B= 54 Kg
Explanation:
The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:
Δm = m₂ – m₁
= V(1/α₂ – 1/α₁)
= 0.05 (1/0.0008935 – 1/ 0.025645)Kg
= 54Kg
The heat transfer is obtained from the energy balance:
ΔU=
+ 
m₂u₂ – m₁u₂ = 
+ 
= m₂u₂ – m₁u₁ –
= V/α₂u₂ - V/α₁u₁ –
=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj
= 203 KJ
Answer:
(c) 4M
Explanation:
The system is a loaded spring. The period of a loaded spring is given by

<em>m</em> is the mass and <em>k</em> is the spring constant.
It follows that, since <em>k</em> is constant,

where <em>C</em> represents a constant.


When the period is doubled,
.

Hence, the mass is replaced by 4M.