The correct answer is: shortest frequency = 7.86*10^15

Explanation: The binding energy of titanium = 3.14*10^6<span> J/mol
</span>The energy required to remove an electron = (3.14*10^6) /(6.023*10^23) = 5.213*10^-18 J<span>
Where 6.023*10^</span>23 = Avagadro number
Since E = hv
Frequency = v = E/h
E = Energy = 5.213*10^-18
h = Planck's constant = 6.626*10^-34
v = (5.213*10^-18) / 6.626*10^-34<span>)
</span><span>v = </span><span>7.86*10^15 </span>

(shortest frequency)
No cluuuueee :/ sowwwwyyy but good luck
Answer:
1. 11 A
2. 240 V
3. 8 Ω
4. 60 C
5. 14400 C
Explanation:
1. Determination of the current.
Voltage (V) = 110 V
Resistance (R) = 10 Ω
Current (I) =?
V = IR
110 = I × 10
Divide both side by 10
I = 110 / 10
I = 11 A
2. Determination of the voltage
Current (I) = 3 A
Resistance (R) = 80 Ω
Voltage (V) =?
V = IR
V = 3 × 80
V = 240 V
3. Determination of the resistance.
Current (I) = 0.5 A
Voltage (V) = 4 V
Resistance (R) =?
V = IR
4 = 0.5 × R
Divide both side by 0.5
R = 4 / 0.5
R = 8 Ω
4. Determination of the charge
Current (I) = 2 A
Time (t) = 30 s
Charge (Q) =?
Q = it
Q = 2 × 30
Q = 60 C
5. Determination of the charge.
We'll begin by converting 20 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
20 mins = 20 × 60
20 mins = 1200 s
Finally, we shall determine the charge as follow:
Current (I) = 12 A
Time (t) = 1200 s
Charge (Q) =?
Q = it
Q = 12 × 1200
Q = 14400 C
Explanation:
maturity also get disorganised
Answer:
a
The current that would be produced is 
b
Yes this arrangement can be used to cancel out earths magnetic field at points well above the Earth's surface.This is because this current loop acts as a magnetic dipole for point above the earth surface
c
No this arrangement can not be used to cancel out earths magnetic field at points on the Earth's surface .this because on the earth surface it shifts from its behavior as a magnetic dipole
Explanation:
From the question we are told that
The magnetic moment of earth is 
The radius of earth generally has a value of 
Magnetic moment is mathematically given as

A is the area of the of the earth(assumption that the earth is circular ) and this evaluated as

Now making
the subject in the above formula



