Question

Assume that during meiosis i, none of the c chromosomes disjoin at metaphase, but they separate into dyads (instead of monads) during meiosis ii. each resultant gamete participated in fertilization with a normal haploid gamete. what combinations will result? check all that apply. check all that apply. two copies of chromosome a, one copy of chromosome b, three copies of chromosome c two copies of chromosome a, two copies of chromosome b, two copies of chromosome c two copies of chromosome a, two copies of chromosome b, one copy of chromosome c two copies of chromosome a, two copies of chromosome b, three copies of chromosome c one copy of chromosome a, two copies of chromosome b, three copies of chromosome c two copies of chromosome a, two copies of chromosome b two copies of chromosome a, two copies of chromosome b, four copies of chromosome c two copies of chromosome a, two copies of chromosome b, five copies of chromosome c

Answer 1

I don’t wanna know that I’m sooo weird I don’t wanna know how