Question

What is the vertex of the graph of y=3x^2+2x+1

Answer 1

vertex = ( - $\frac{1}{3}$, $\frac{2}{3}$)

given a parabola in standard form : ax² + bx + c (a ≠ 0 )

then the x-coordinate of the vertex = - $\frac{b}{2a}$

y = 3x² + 2x + 1 is in standard form

with a = 3, b = 2 and c = 1

$x_{vertex}$ = - $\frac{2}{6}$ = - $\frac{1}{3}$

substitute this value into the equation for y- coordinate of vertex

$y_{vertex}$ = 3( - $\frac{1}{3}$)² + 2(- $\frac{1}{3}$) + 1

= $\frac{1}{3}$ - $\frac{2}{3}$ + $\frac{3}{3}$ = $\frac{2}{3}$

vertex = ( - $\frac{1}{3}$, $\frac{2}{3}$)

Answer 2

Answer:

B on edge

Step-by-step explanation: